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2 years ago

WHATS IS THE HEIGHT OF THE FLAGPOLE?

Mathematics

1 answer:

ch4aika [34]2 years ago

5 0

Answer

18 Ft

Step-by-step explanation:

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If x = a sin α, cos β, y = b sin α.sin β and z = c cos α then (x²/a²) + (y²/b²) + (z²/c²) = ?

Oduvanchick [21]

$\large\underline{\sf{Solution-}}$

<u>Given:</u>

$\rm \longmapsto x = a \sin \alpha \cos \beta$

$\rm \longmapsto y = b \sin \alpha \sin \beta$

$\rm \longmapsto z = c\cos \alpha$

Therefore:

$\rm \longmapsto \dfrac{x}{a} = \sin \alpha \cos \beta$

$\rm \longmapsto \dfrac{y}{b} = \sin \alpha \sin \beta$

$\rm \longmapsto \dfrac{z}{c} = \cos \alpha$

Now:

$\rm = \dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} }$

$\rm = { \sin}^{2} \alpha \cos^{2} \beta + { \sin}^{2} \alpha \sin^{2} \beta + { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha (\cos^{2} \beta + \sin^{2} \beta )+ { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha \cdot1+ { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha + { \cos}^{2} \alpha$

$\rm = 1$

<u>Therefore:</u>

$\rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } = 1$

5 0

2 years ago

Half the sum of X and Y decreased by 1/3 why

Allushta [10]

What is the question here.
(1/2)(X+Y)-(1/3)

8 0

3 years ago

Please help and explain how to solve these! Thanks

spin [16.1K]

2. C
Slope = 40/8 = 5
Slope of graph c = 5/1 = 5

3. D
Slope = 9/3 = 3
Slope of graph d = 81/27 = 3

3 0

2 years ago

Read 2 more answers

The tickets for an upcoming ballet cost $54 per person. Mrs. Anastos wants to purchase 16 tickets for her friends. What

MissTica

Answer:

the answer is $864 pls give brainliest

Step-by-step explanation:

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3 years ago

3a x 5b x 7c = 39375, then find value of 7a - 2b + 3c

garik1379 [7]

Answer:

Step-by-step explanation:

Simplifying

(7a + -2b) + -1[2(3a + -1c) + -3(2b + -3c)] = 0

Remove parenthesis around (7a + -2b)

7a + -2b + -1[2(3a + -1c) + -3(2b + -3c)] = 0

7a + -2b + -1[(3a * 2 + -1c * 2) + -3(2b + -3c)] = 0

7a + -2b + -1[(6a + -2c) + -3(2b + -3c)] = 0

7a + -2b + -1[6a + -2c + (2b * -3 + -3c * -3)] = 0

7a + -2b + -1[6a + -2c + (-6b + 9c)] = 0

Reorder the terms:

7a + -2b + -1[6a + -6b + -2c + 9c] = 0

Combine like terms: -2c + 9c = 7c

7a + -2b + -1[6a + -6b + 7c] = 0

7a + -2b + [6a * -1 + -6b * -1 + 7c * -1] = 0

7a + -2b + [-6a + 6b + -7c] = 0

Reorder the terms:

7a + -6a + -2b + 6b + -7c = 0

Combine like terms: 7a + -6a = 1a

1a + -2b + 6b + -7c = 0

Combine like terms: -2b + 6b = 4b

1a + 4b + -7c = 0

Solving

1a + 4b + -7c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4b' to each side of the equation.

1a + 4b + -4b + -7c = 0 + -4b

Combine like terms: 4b + -4b = 0

1a + 0 + -7c = 0 + -4b

1a + -7c = 0 + -4b

Remove the zero:

1a + -7c = -4b

Add '7c' to each side of the equation.

1a + -7c + 7c = -4b + 7c

Combine like terms: -7c + 7c = 0

1a + 0 = -4b + 7c

1a = -4b + 7c

Divide each side by '1'.

a = -4b + 7c

Simplifying

a = -4b + 7c

8 0

2 years ago