Bot 2 will click more times in 10 seconds, because when you divide 16 by 2 to get its unit rate it is 8 clicks per second. Times that by 10 and you only get 80, whereas if you divide 30 by 3 the unit rate is 10. At this rate, by 10 seconds it will have clicked 100 times. Bot 2 clicks 20 more times than Bot 1 in 10 seconds.
Answer:
It will take Machine A 20 additional minutes.
Step-by-step explanation:
First we have get the rate of work per hour, Machine A builds 1/2 of a car per hour, while Machine B builds 1/3 of a car per hour.
Using this we can determine the amount of work that has been done so far in one hour before Machine B broke down:
1/2 + 1/3 = 3/6 + 2/6 = 5/6
Now we can produce an equation accordingly to determine how much time it'll take machine a to finish the job:
5/6 + 1/2x = 1
1/2x = 1/6
x = 1/3 hours = 20 minutes
Note: In the question you typed "how much additional time will it take machine b to finish" but I think you meant machine a because machine b broke down. Please correct me if I'm wrong.
Hope this helps! And let me know if you have any questions!
Answer:
C
Step-by-step explanation:
I’m not entirely sure if this is right but I hope I helped.
<span>p1=44/88=.50; p2=57/85=.67.
Under the null hypothesis of no difference, we pool the data to estimate the
common p of (44+57)/(88+85)=.584.
The test statistic is (.67-.50)/sqrt[(.584)(1-.584)(1/88 + 1/85)]=2.268 (which is stat sig. at a .095 level).</span>
