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V125BC [204]
3 years ago
10

BRAINLIEST HELPPPPPO

Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Question 5

To use the quadratic formula, we need to rewrite the equation so that all the terms are on one side: by subtracting (x+13) from both sides, we get that x^2-x-6=0. The quadratic formula tells us that the roots of this are \frac{-b \pm \sqrt{b^2-4ac}}{2a}, where a=1, b=-1, and c=-6. This is equal to \frac{-(-1)\pm \sqrt{(-1)^2-4(1)(-6)}}{2(1)} = \frac{1 \pm 5}{2}, which gives us the two roots -2 and 3.

Question 7

If you look at the attached graph, you will see that the graph of x^2-x-6 intersects the x-axis at the points (-2,0) and (3,0).

Question 8

The roots are the same. Both finding the x-intercepts and solving for the roots of a quadratic using the quadratic formula will give the values of x for which the function value is zero.

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Answer:

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Step-by-step explanation:

From a first glance, since g(x), is skinnier than f(x), meaning that it is increasing faster, so I know that I can eliminate options A & B since the coefficient on x needs to be greater than 1.

We can then look and see that g(1) = 4 as shown by the point given to us on the graph.

To find the right answer we can find g(1) for options C & D and whichever one matches the point on the graph is our correct answer. e

Option C:

once we plug in 1 for x, our equation looks like

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1^2 = 1, and 4(1) = 4,

so g(1) = 4. and our point is (1,4).

This is the same as the graph so this is the CORRECT answer.

If you want to double check, you can still find g(1) for option D and verify that it is the WRONG answer.

Option D:

once we plug in 1 for x, our equation looks like

16(1)^2

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so g(1) = 16. and our point is (1,16).

This is different than the graph so this is the WRONG answer.

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3 years ago
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Answer:

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Step-by-step explanation:

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