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Lady bird [3.3K]
3 years ago
9

Plsss helppppp I’ll mark u brainlist no links pls

Mathematics
1 answer:
Basile [38]3 years ago
3 0

Step-by-step explanation:

you flip it from the line, match the letters (Z woube be C, X would be A, etc.) and then writw the new coordinates

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What is a number decreased by 4 is more than -1 . you have to write an inequality .
rosijanka [135]
You would just need to make an inequality from the description. You would make "x" the number. The answer would be "x-4>-1"
3 0
3 years ago
Write each expression without the absolute value symbol |3x+12|
klasskru [66]

Answer:

Step-by-step explanation:

|3x+12|

one is as it is                                     one is the negative value of it

3x + 12                                                   - (3x + 12)

                                                               - 3x - 12

That is because both negative and positive values put in am absolute value become positive.

3 0
2 years ago
I need help on this question as well.
Y_Kistochka [10]

8 is the answer, because 4 x 8 = 32

7 0
3 years ago
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CAN SOMEONE PLZ HELP ME?? PLZ DO YOU KNOW ABOUT Coordinate Planes??!! AHH
aev [14]

Answer:

Step-by-step explanation:

8 0
3 years ago
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The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
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