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kumpel [21]
3 years ago
8

f(x) = x4 - 50x2 + 3 (a) Find the intervals on which f is increasing. (Enter the interval that contains smaller numbers first.)

( , ) ∪ ( , ) Find the intervals on which f is decreasing. (Enter the interval that contains smaller numbers first.) ( , ) ∪ ( , ) (b) Find the local minimum and maximum values of f. (min) (max) (c) Find the inflection points. ( , ) (smaller x value) ( , ) (larger x value) Find the intervals on which f is concave up. (Enter the interval that contains smaller numbers first.) ( , ) ∪ ( , ) Find the interval on which f is concave down. ( ,

Mathematics
1 answer:
shtirl [24]3 years ago
5 0

Answer:

  (-5, 0) ∪ (5, ∞)

Step-by-step explanation:

I find a graph convenient for this purpose. (See below)

__

When you want to find where a function is increasing or decreasing, you want to look at the sign of the derivative. Here, the derivative is ...

  f'(x) = 4x^3 -100x = 4x(x^2 -25) = 4x(x +5)(x -5)

This has zeros at x=-5, x=0, and x=5. The sign of the derivative will be positive when 0 or 2 factors have negative signs. The signs change at the zeros. So, the intervals of f' having a positive sign are (-5, 0) and (5, ∞).

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EastWind [94]
1 purse and 1 watch is 27€
2 purse and 1 watch is 41€

So we can see the watch is constant means 1 watch is every time but purse is increase by 1 in the next expression

So 41-27 = 14€ is one purse
because the watch is every time one, so the next value increase is by purse

1purse and 1watch = 27
We know,
1 purse is 14€
So 27-14=13€ is one watch

We can check by
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Hope it help you!¡

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Elimination using addition and subtraction. <br> -4x+4y=-20<br> -2x+4y=-2
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I would subtract the 2nd from the first one

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