What is 6 1/3 - 1 1/2 =
1 answer:
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The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L