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Katen [24]
3 years ago
15

19. Which one of the following statements expresses a true proportion?

Mathematics
1 answer:
choli [55]3 years ago
7 0
That would be : 3:5 = 12:20....because 3/5 = 12/20
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If p(x)=2x^2 -4 and q(x)=x-3, what is (p*q)(x)
Natasha_Volkova [10]

Answer:

2x^3 - 6x^2 - 4x + 12.

Step-by-step explanation:

(p*q) (x)  = (2x^2 - 4)(x - 3)

= 2x^3 - 6x^2 - 4x + 12.

4 0
3 years ago
Read 2 more answers
Max is thinking of a number, which he calls n. He adds 8 and then doubles the sum.
Veronika [31]

The equation representing Max's number is 2\times(x+8).

<h3>What is an equation?</h3>

In its simplest form in algebra, the definition of an equation may be a mathematical statement that shows that two mathematical expressions are equal. It consists of variables dependent and independent variables. They can be linear or non-linear in nature.

Let the number Max is thinking be 'x'

He adds 8 to the number and then he doubles the sum.

Sum means we are adding a number to x, in this case it is 8.

Double the number means twice the given number in this case it is twice the sum of number with 8.

As per the statement:

The expression to represents Max's number

=2\times(x+8)

To know more about equations visit:

brainly.com/question/15457147

#SPJ9

7 0
1 year ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
−−→ LO bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . LO → bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . What is the value
Sindrei [870]

Answer:

7.2

Step-by-step explanation:

Given that in triangle LMN, LO is angle bisector of angle L.

LN =10 and LM =18

By angle bisector theorem for triangles we have

LN/LM = NO/MO

Substitute the values for known things and x for MO

We get

10/18 = 4/x

Or cross multiply to get

10x=72

x=7.2

So answer is 7.2

3 0
3 years ago
Town B is 6 miles due north of town A, and town C is due east of town A. It is 11 miles from town B to town C. Find the distance
nadya68 [22]

Answer:

12.53 miles

Step-by-step explanation:

6² + 11² = x²

36 + 121 = x²

157 = x²

x = 12.53 miles

4 0
3 years ago
Read 2 more answers
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