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Juli2301 [7.4K]
3 years ago
15

Please help me on this!

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

y = -4/5x + 1

Step-by-step explanation:

If those blue points are on the exact point, i can't really tell

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Order the integers {0, |-20|, -3, 19, -13} from least to greatest
tatiyna

Answer:

-20, -13, -3 0, 19

Step-by-step explanation:

With negative the higher the number the lower the value

4 0
3 years ago
PLEASE HELP!! brainliest if correct!!
Sonja [21]
Graph #1: No
Graph #2: Yes
Graph #3: No
Graph #4: No
Graph #5: No
Graph #6: Yes

Reasoning:

The vertical line test is a test that determines wether a graph is a function or a relation. The vertical line test shows that if you construct a vertical line through any point on the graph, then the vertical line should only intercept the graph once for it to be a function.
6 0
2 years ago
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
Read 2 more answers
What is the area of this figure?
matrenka [14]
There is 2 figure here, a triangle and a parallelogram.
Area of parallelogram=base * height
                                   A=9 * 5
                                   A=45m²
Area of triangle= \frac{1}{2} (base * height)
                        A=\frac{1}{2} (9*8)
                        A=\frac{1}{2}72
                        A=36m²
36+45=81m²
The area of this figure is 81m²
3 0
4 years ago
HELP!!! Choose the best answer.
maxonik [38]

Answer:

x^3y^2+x^2y^3-x^2-y^2

Step-by-step explanation:

I will edit my answer if you need my explanation.

If this has helped you please mark as brainliest

4 0
3 years ago
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