Answer:
Step-by-step explanation:
Corresponding scores before and after taking the course form matched pairs.
The data for the test are the differences between the scores before and after taking the course.
μd = scores before taking the course minus scores before taking the course.
a) For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
b) We would assume a significance level of 0.05. The P-value from the test is 0.65. The p value is high. It increases the possibility of accepting the null hypothesis.
Since alpha, 0.05 < than the p value, 0.65, then we would fail to reject the null hypothesis. Therefore, it does not provide enough evidence that scores after the course are greater than the scores before the course.
c) The mean difference for the sample scores is greater than or equal to zero
Whats the problem? just substitute. For example: 3x-5 if x=4 so what you do is this; 3(4)-5=7
Answer:
the square root of 197
Step-by-step explanation:
delta x=14
delta y=1
therefore with the Pythagorean theorem, the hypotenuse/distance is the square root of 197
16.4 would be the greatest and 15.6 would be the least due to 2.5% equaling 0.4 and adding and subtracting it from 16.
Answer: 33
To maximize the length of the third side, which I'll call x, it needs to be the longest side.
So by the triangle inequality theorem, 19+15>x, meaning the maximum whole number value of x is 33.
