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3 years ago

I need help !! I’m stuck on this question

Mathematics

1 answer:

Nataliya [291]3 years ago

5 0

Answer: D. a+2s=$22

a+3s=$28

Step-by-step explanation:

Let's take a look at our variables. They are a and s, the a standing for the cost of an adult ticket and the s standing for the cost of the student ticket. In both situations, only one adutl ticket was purchased, so we start off out equations with only an a. As for the student tickets, Alex buys 2 and Jen buys 3.

a+2s

a+3s

The whole point of writing this equation is to find the cost of the tickets, so we would both equal it to the amount they spent.

a+2s=$22

a+3s=$28

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1)
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2)
$x^2-5x-6=0 \\
x^2-6x+x-6=0 \\
x(x-6)+1(x-6)=0 \\
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3)
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4)
$x^2+8x-8=0 \\ \\
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\sqrt{\Delta}=\sqrt{96}=\sqrt{16 \times6}=4\sqrt{6} \\ \\
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5)
$2x^2+12x=0 \\
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x=0 \ \lor \ x=-6 \\
\boxed{x=-6 \hbox{ or } x=0}$

6)
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7)
$x^2-x+2=0 \\ \\
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8)
$3x^2-6x+1=0 \\ \\
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9)
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10)
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4 years ago

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kaheart [24]

y = 90°

Solution:

The reference image for the answer is attached below.

The sum of opposite interior angles is equal to the exterior angles.

m∠BAC + m∠ACB = 110°

m∠BAC + 70° = 110°

m∠BAC = 110° – 70°

m∠BAC = 40°

m∠BAD + m∠DAC = 40°

x + x = 40°

2x = 40°

Divide by 2 on both sides of the equation.

x = 20°

In triangle DAC,

Sum of all the angles of a triangle = 180°

m∠DAC + m∠ACD + m∠CDA = 180°

20° + 70° + m∠CDA = 180°

90° + m∠CDA = 180°

m∠CDA = 180° – 90°

m∠CDA = 90°

∠CDA and y lies on the straight line. So they form a linear pair.

y + m∠CDA = 180°

y + 90° = 180°

y = 180° – 90°

y = 90°

The value of y is 90°.

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