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NARA [144]
3 years ago
5

3÷5(6×7) - 4Plz I need help​

Mathematics
2 answers:
myrzilka [38]3 years ago
8 0

Answer:

- 3 and 69/70

Step-by-step explanation:

3 ÷ 5(6 × 7) - 4

3 ÷ 5(40) - 4

3 ÷ 210 - 4

1/70 ÷ 4

- 3 and 69/70

ivolga24 [154]3 years ago
4 0

Answer:

21.2

Step-by-step explanation:

3/5(42)-4

0.6(42)-4

25.20-4

21.2

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A confectioner has 300 pounds of a chocolate that is 1 part cocoa butter to 7 parts caramel. How much chocolate that is 1 part c
anygoal [31]
Let's call our unknown quantity n. We'll need to add n lbs of chocolate with a 1/15 ratio of cocoa butter to caramel to 300 lbs of chocolate with a 1/7 ratio of cocoa butter to caramel to yield 300+n lbs of chocolate with a 1/9 ratio of cocoa butter to caramel. We can set this up as an equation, but it's important to note something first: the ratio of the <em>caramel to the cocoa butter</em> is provided, but this is not the same thing as the <em>fraction of the chocolate the cocoa butter takes up</em>.

The 300 pounds of chocolate have 1 + 7 = 8 parts of cocoa butter and caramel total, which means that cocoa butter takes up 1/8 of those total parts; the n pounds we're adding on has 1 + 15 = 16 total parts, which means the cocoa butter takes up 1/16 of those; and the 300+n pounds being produced have 1 + 9 = 10 total parts, so the cocoa butter takes up 1/10 of those parts. With this in mind, we can set up the following equation:

300\big( \frac{1}{8}\big)+n\big( \frac{1}{16}\big)=(300+n)\big( \frac{1}{10}\big)

which we can rewrite as

\frac{300}{8}+ \frac{n}{16}= \frac{300+n}{10}

From here, it would be helpful to combine the fractions on the left side of the equation. To do this, we'll convert the denominator of \frac{300}{8} to 16, multiplying it by \frac{2}{2} to obtain the fraction \frac{600}{16}. Combining that with \frac{n}{16}, we have:

\frac{600+n}{16}= \frac{300+n}{10}

To get rid of the denominator on the left, we'll multiply both sides of the equation by 16, and to eliminate the one on the right, we'll multiply both sides by 10:

(10)(16)\big( \frac{600+n}{16}\big)=\big( \frac{300+n}{10}\big)(10)(16)

Simplifying:

10(600+n)=(300+n)16\\ 6000+10n=4800+16n

And finally, we solve for n:

6000-4800=16n-10n\\ 1200=6n\\ 200=n

So, the confectioner needs 200 lbs of chocolate that's 1 part cocoa butter and 15 parts caramel.
8 0
4 years ago
The graph for the equation y = negative 2 x + 1 is shown below.
Alex

Answer:

  y = -1/2 (4 x + 2)

Step-by-step explanation:

A system of two equations with no solution will consist of equations for <em>parallel lines</em>. The line will be parallel if they have the same slope (x-coefficient) and different y-intercepts.

The given line has a slope of -2, so eliminating the last two choices.

The first two choices can be expanded to slope-intercept form:

  y = negative 2 (x minus one-half)  ⇒  y = -2x +1 . . . same as given line

  y = negative one-half (4 x + 2)  ⇒  y = -2x -1 . . . parallel line

There will be no solution if another equation is ...

  y = -1/2(4x +2)

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Answer:

36+15+15+15+15

Step-by-step explanation:

For the surface area we need to add up all the areas in the pyramid:

  • area of the base
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Area of the base:

the base is a square, and the area of a square is given by:

a_{base}=l^2

where l is the length of the side: l=6, thus:

a_{base}=(6)^2\\a_{base}=36

Area of the triangles:

one triangle has the area given by the formula:

a_{triangle}=\frac{b*h}{2}

where b is the base of the triangle: b=6

and h is the height of the triangle: h=5, thus we have the following:

a_{triangle}=\frac{6*5}{2} \\\\a_{triangle}=\frac{30}{2} \\\\a_{triangle}=15

the expression that represents the surface area of the pyramid is:

a_{base}+area_{triangle}+area_{triangle}+area_{triangle}+area_{triangle}

substituting our values:

36+15+15+15+15

which is option B

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Find two numbers that multiply to give ac (in other words a times c), and add to give b.

Rewrite the middle with those numbers:

Step 3: Factor the first two and last two terms separately:

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