Y=mx+b is the equation we must fill out, with x and y being their respective coordinates, m being the slope, and b being the y-intercept. The y intercept will be at (0, y), and the beginning of this problem already gives us the y-intercept: -4.
We now know y=mx-4. To find the slope, m, we’ll plug in one of the coordinates: (5, 1). The new equation is 1=m(5)-4. Solve this to get 5=m(5), and then m=1.
Now that we know the slope and y-intercept, we can conclude that the equation is y=x-4.
Answer:
The area of the parallelogram is:_______________________________________________________
in² = 1174 ⅛ in² = 1174.125 in² .
_______________________________________________________Explanation:_______________________________________________________Area of a parallelogram:
_______________________________________________________ A = base * height = b * h ;
From the figure (from the actual "question"):
_______________________________________ b = 50.5 in.
h = 23.25 in.
____________________________________________________________Method 1) A = b * h =
= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>
____________________________________________________________Method 2) A = b * h =
= (50 ½ in) * (23 <span>¼ in) =
= (</span>

in) * (

<span> in) ;
</span>
___________________________________________________________Note: "50 ½ " = [(50*2) + 1 ] / 2 =

;
Note: "23 ¼ " = [(23*4) + 1 ] / 4 =

;
____________________________________________________________
→ A = (

in) * (

in) ;
→ A =

in² =

in² ;
→ A = (9393/8) in² =
→
A =
in² = 1174 ⅛ in² = 1174.125 in² .
________________________________________________________
Answer:
20
Step-by-step explanation:
130-110
Q3-Q1=IQR
Hope this helps!
Answer:
m<ADC = 42°
Step-by-step explanation:
Based on the inscribed angle theorem, the inscribed angle, m<ADC is ½ the measure of minor arc AC.
If minor arc is given as 84°, therefore:
m<ADC = ½(84)
m<ADC = 42°