Answer:
Volume of HCl require = 6 mL
Explanation:
Given data:
Volume of HCl require = ?
Molarity of HCl solution = 1.60 M
Volume of NaOH = 48.0 mL
Molarity of NaOH = 0.200 M
Solution:
Formula:
M₁V₁ = M₂V₂
By putting values,
1.60 M×V₁ = 0.200 M×48.0 mL
V₁ = 0.200 M×48.0 mL/1.60 M
V₁ = 9.6 M .mL /1.60 M
V₁ = 6 mL
The smallest particle of a covalently bonded compound is an atom.
They are grouped together because they share certain physical and chemical properties. For instance, metals are dense, shiny, good conductors of heat and electricity, and they easily lose electrons in chemical reactions. In contrast, nonmetals have the opposite properties.
6.5 moles of AgCl can be formed from 6.5 moles of Ag.
STOICHIOMETRY:
According to this question, silver reacts with hydrochloric acid to form silver chloride and hydrogen gas as follows:
2Ag + 2HCl → 2AgCl + H2
Based on this balanced equation, 2 moles of silver (Ag) produces 2 moles of silver chloride (AgCl).
This means that 6.5 moles of Ag will produce (6.5 × 2)/2 = 6.5 moles of AgCl.
Learn more about stoichiometry at: brainly.com/question/9743981?referrer=searchResults