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3 years ago

What element are diamonds composed of

2 answers:

6 0

Diamonds are composed almost entirely of the element carbon maybe sometimes with impurities in them, such as nitrogen (i.e., pure diamonds are entirely carbon). The element carbon comes in three different natural forms, or allotropes: diamond, graphite, and amorphous. :p

never [62]3 years ago

3 0

Answer:

diamonds are carbon based and have a giant covalent structure

Explanation:

This is what gives diamonds its strength and rigidity.

Diamonds are different from graphite due to the way the atoms are arranged

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Which set of atoms will form an ionic compound

ZanzabumX [31]

Answer:

The Ionic compound is held by ionic bonding and this ionic bond forms between a metal and a non-metal. Here the calcium atom is the metal and the oxygen atom is a non-metal this set of atoms will form an ionic compound.

5 0

3 years ago

An elementary reaction _____. converts reactants to products in a single step never needs a catalyst has only elements as produc

IgorLugansk [536]

Answer:

chain

Explanation:

I say that its chain because of the porreqwue

8 0

3 years ago

________ are neutral particles found in the nucleus of an atom.

IRISSAK [1]

Neutrons is your answer my friend

3 0

3 years ago

Read 2 more answers

A chemist adds of a zinc nitrate solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has a

Ray Of Light [21]

Answer:

5.3 × 10⁻³ kg

Explanation:

There is some info missing. I think this is the original question.

A chemist adds 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

We have 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution. The moles of zinc nitrate are:

0.1350 L × 0.21 mol/L = 2.8 × 10⁻² mol

The molar mass of zinc nitrate is 189.36 g/mol. The mass corresponding to 2.8 × 10⁻² moles is:

2.8 × 10⁻² mol × 189.36 g/mol = 5.3 g

1 kilogram is equal to 1000 grams. Then,

5.3 g × (1 kg/1000 g) = 5.3 × 10⁻³ kg

8 0

3 years ago

A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?

Katen [24]

Answer:

T2 = 260 K

Explanation:

Given data:

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K

V1 = 1.75 L

P2 = 210.0 kPa

V2 = 1.30 L

To find:

T2 = ?

Formula:

$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$

$T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}$

Calculation:

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

T2 = 260 K

8 0

4 years ago