Answer:
6
Step-by-step explanation:
sin(angle) = opposite/hypotenuse
sin(60) = a/4√3
√3/2 = a/4√3
a = (√3/2)(4√3) = 2(3) = 6
We can not evaluate it with real numbers, because there is no real number that multiplies itself twice and gives -25.
The answer is an imaginary number.
√-25 = 5i where i = √-1
So it can only be computed using imaginary numbers.
Answer:
215
Step-by-step explanation:
The 238 taking Finite Math includes those taking Finite Math and Statistics. Subtracting out the 23 who are taking both leaves 215 taking Finite Math only.
<h3>The exact probability that the blue ball is drawn first and the red ball is drawn second is
![\frac{1}{132}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B132%7D)
</h3>
<em><u>Solution:</u></em>
<em><u>The probability of an event is given as:</u></em>
![Probability = \frac{ \text{ number of favorable outcomes }}{ \text{ total number of possible outcomes }}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B%20%5Ctext%7B%20number%20of%20favorable%20outcomes%20%7D%7D%7B%20%5Ctext%7B%20total%20number%20of%20possible%20outcomes%20%7D%7D)
Given that,
There are 12 balls in a bag
One is blue and one is red
Favorable outcome = blue ball is drawn first
Favorable outcome = 1
Therefore,
![Probability = \frac{1}{12}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%7D%7B12%7D)
Now, without replacement, red ball is drawn second
Therefore,
Total possible outcomes = 12 - 1 = 11
![Probability = \frac{1}{11}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%7D%7B11%7D)
<em><u>What is the exact probability that the blue ball is drawn first and the red ball is drawn second?</u></em>
![Total\ probability = \frac{1}{12} \times \frac{1}{11} = \frac{1}{132}](https://tex.z-dn.net/?f=Total%5C%20probability%20%3D%20%5Cfrac%7B1%7D%7B12%7D%20%5Ctimes%20%5Cfrac%7B1%7D%7B11%7D%20%3D%20%5Cfrac%7B1%7D%7B132%7D)
Thus the exact probability that the blue ball is drawn first and the red ball is drawn second is ![\frac{1}{132}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B132%7D)