Begin with cos(θ) = 5/13, θ in Quadrant IV
you should distinguish the 5-12-13 right-angled triangle
and then cosØ = adjacent/hypotenuse
x = 5, r = 13 , y = -12, since Ø is in IV
and sinØ = -12/13
also tan(ϕ) = −√15 = -√15/1 = y/x and ϕ is in II,
y = √15 , x = -1
r^2 = x^2 + y^2 = 15+1 = 16
r = 4
sinϕ = √15/4 , cosϕ = -1/4
you must know that:
cos(θ − ϕ) = cosθcosϕ + sinθsinϕ
= (5/13)(-1/4) + (-12/13)(√15/4)
= -5/52 - 12√15/52
= (-5-12√15)/52
If you have some thing like x^2 + x + x^3 + x^2 the correct order would be x^3 + x^2 + x^2 + x.
If every 2 sec = x that well mean that symmetry and asympotes well go together .
I'm pretty sure it's
q= 4(9)+4(6)
This is true, since both are quadrilaterals, so they have 4 sides and therefore 4 angles. There are 9 rhombuses, so each has 4 angles. This would mean you'd have to multiply each quadrilateral by 4 to find your answer.
I hope this helps a little.
Answer:
E
Step-by-step explanation:
The equation of proportion is
y = kx ← k is the constant of proportionality and
k = 
Substitute the values from the table into the equation for k, that is
k = 
= 
= 
=
