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3 years ago

Find the area of this semi-circle with radius, r = 2cm.

Mathematics

1 answer:

DanielleElmas [232]3 years ago

7 0

Answer:

Step-by-step explanation:

<h2>Hi there</h2><h3>to understand this </h3><h3>you need to know about</h3>

algebra
circle
area of semi-circle=½×πr²

it says to figure out the area of <u>semi-circle </u>not full circle

using the formula of area of semi-circle

=½×3.14 × 2²

=2×3.14

=6.28

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A prism has a square base with a side length of 4 1 2 4 1 2 feet. The height of the prism is 6 feet. What is the volume of the p

dusya [7]

We have been given that a prism has a square base with a side length of 4 1/2 feet. The height of the prism is 6 feet. We are asked to find the volume of the prism.

We know that volume of prism is base area times height.

$\text{Area of base}=\text{Area of square}=\text{Side length}^2$

$\text{Area of base}=(4\frac{1}{2})^2$

$\text{Area of base}=(\frac{9}{2})^2$

$\text{Area of base}=\frac{9^2}{2^2}$

$\text{Area of base}=\frac{81}{4}$

$\text{Volume of prism}=\frac{81}{4}\times 6$

$\text{Volume of prism}=\frac{81}{2}\times 3$

$\text{Volume of prism}=\frac{243}{2}$

$\text{Volume of prism}=121\frac{1}{2}$

Therefore, the volume of prism is $121\frac{1}{2}\text{ ft}^3$ and option D is the correct choice.

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4 years ago

A factory produces 40 cars per week. What is the percentage in the production rate if it changes from 40 cars per week to 100 ca

Travka [436]

Answer:

100/40=2.5 or 250%

250% in production rate should be your answer.

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3 years ago

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4 years ago

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The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

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3 years ago

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almond37 [142]

Answer:

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Step-by-step explanation:

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