Question

A ball thrown in the air has a height of y = - 16x² + 50x + 3 feet after x seconds. a) What are the units of measurement for the rate of change of y? b) Find the rate of change of y between x = 0 and x = 2?

Answer 1

Answer:

a)$ms^{-1}$

b)$71ms^{-1}$

Solution:

a)

we are finding the derivative from position to velocity thus

units = $ms^{-1}$

b)

$m=\frac{y(2)-y(0)}{2-0}=\frac{139+3}{2}=71ms^{-1}$