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Blababa [14]
3 years ago
6

Solve the proportion?

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0
2x-4 = 4x+ 16

-20= 2x

x=10

1) cross multiply and distribute
2)move the x to one side, and the numbers without the x to the other, be sure to change signs
3)solve
4)x=?

use the top 4 steps for all of the questions like this

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Given tz/zx=tw/wy. if tx =53, find ty
s2008m [1.1K]

Answer:

ty = 53

Step-by-step explanation:

Given

\frac{tz}{zx} = \frac{tw}{wy}

Cancel the z on the numerator/denominator of the left side and

Cancel the w on the numerator/denominator of the right side, leaving

\frac{t}{x} = \frac{t}{y}

Cross- multiply

ty = tx ← tx = 53, hence

ty = 53

6 0
3 years ago
The volume of the cube is 512 cubic units what is its edge length
Studentka2010 [4]
The proper equation used to solve this is (let's use E for edge) E=V^1/3
The V stands for volume. So, your equation is 512^1/3
Your answer is 8, which is what you get when you work this out.
8 0
3 years ago
Hi, I am very stuck on questions 17 and 18. Can someone help please? Thanks
NISA [10]

9514 1404 393

Answer:

  17) x = 10√2

  18) x = 4√6

Step-by-step explanation:

These problems rely on your knowledge of the side ratios of special triangles

  45°-45°-90° triangle: 1 : 1 : √2

  30°-60°-90° triangle: 1 : √3 : 2

__

17) 5 is the short side of the isosceles right triangle, so its hypotenuse is 5√2. That length is the shortest side of the 30/60/90 triangle, so its longest side is 2 times that:

  x = 10√2

__

18) 8 is the longest side of the 30/60/90 triangle, so its long leg will be 8(√3)/2 = 4√3. The hypotenuse of the isosceles right triangle is √2 times that, so ...

  x = (4√3)(√2)

  x = 4√6

6 0
3 years ago
the length of a rectangle is 50 feet less than its width. If the perimeter of the field is 840 feet, find the length of the fiel
LiRa [457]
look\ at\ the\ picture\\\\2a+2(a-50)=840\\\\2a+2a-100=840\\\\4a-100=840\ \ \ /+100\\\\4a=940\ \ \ \ /:4\\\\a=235\ (ft)\\\\a-50=235-50=185\ (ft)\\\\Answer:lenght=185\ ft;\ width=235\ ft.

8 0
3 years ago
A force of 18 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i
Wittaler [7]

Answer: 18.75 lb.ft

Step-by-step explanation:

Given

Force required to stretch spring 8 in. is 18 lb

it can be written

\Rightarrow F=kx\\\Rightarrow 18=k(8)\\\\\Rightarrow k=\dfrac{18}{8}=\dfrac{9}{2}\ lb/in.

Work done in stretching from its natural length to 10 in.

\Rightarrow W=\dfrac{1}{2}kx^2\\\\\Rightarrow W=0.5\times \dfrac{9}{2}\times (10)^2\\\\\Rightarrow W=225\ lb.in.\ or\\\Rightarrow W=18.75\ lb.ft

8 0
3 years ago
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