Answer:
Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.
Step-by-step explanation:
Given the inequality function
0.7S+0.5L≤11 where S represent the number of sunflower plants and L represent the number of lily plants Ezra's water supply can water, if Ezra waters 10 lily plants, then we can calculate the maximum amount of sunflower plant that he can water with the remaining amount of water by simply substituting L = 10 into the inequality function as shown;
0.7S+0.5L≤11
0.7S+0.5(10)≤11
0.7S+5≤11
Taking 5 to the other side:
0.7S≤11-5
0.7S≤6
S≤6/0.7
S≤8.57
This shows that Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.
Answer:
0.875 is the equivalent fraction
Answer:
(B) 5/6 ·13÷4
(C) 5/6 ÷4·13
(D) 5/6 · 13/4
Step-by-step explanation:
Amount of paint per can = ![\[\frac{5}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B5%7D%7B6%7D%5C%5D)
liters.
Number of cans used to paint 4 cars = 13
Total amount of paint used for 4 cars = ![\[13 * \frac{5}{6}\]](https://tex.z-dn.net/?f=%5C%5B13%20%2A%20%5Cfrac%7B5%7D%7B6%7D%5C%5D)
liters.
= ![\[\frac{13 * 5}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B13%20%2A%205%7D%7B6%7D%5C%5D)
liters.
= ![\[\frac{65}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B6%7D%5C%5D)
liters.
Total amount of paint used for 1 car = ![\[\frac{65}{6} \div 4\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B6%7D%20%5Cdiv%204%5C%5D)
liters.
= ![\[\frac{65}{24}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B24%7D%5C%5D)
liters.
Of the given options, option B,C and D correspond to the same value.
8a) The monthly rainfall is 3.6
8b) Deviation for May is 1
Deviation for June is 2.725
Deviation for July is 0.65
8c) Yes, the average annual rainfall was exceeded by 0.525
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