Answer:
A
Step-by-step explanation:
Complex roots of quadratic functions occur when the <u>discriminant is negative</u>.
<u>Discriminant</u>

Evaluate the discriminant of each of the given equations.



As -24 < 0 the equation will have complex roots.




As 41 > 0 the equation does not have complex roots.




As 48 > 0 the equation does not have complex roots.




As 33 > 0 the equation does not have complex roots.
Learn more about discriminants here:
brainly.com/question/27444516
brainly.com/question/27869538
Learn more about complex roots here:
brainly.com/question/26344541
Answer:
dy=9-y
dx=x
Step-by-step explanation:
Hello!
To find the equation of a line parallel to y = 3x - 3 and passing through the point (4, 15), we need to know that if two lines are parallel, then their slopes are equivalent.
This means that we create a new equation in slope-intercept form, which includes the original slope, which is equal to 3.
In slope-intercept form, we need a y-intercept. So, we would substitute the given ordered pair into the new equation with the same slope and solve.
Remember that slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept.
y = 3x + b (substitute the ordered pair (4, 15))
15 = 3(4) + b (simplify)
15 = 12 + b (subtract 12 from both sides)
3 = b
Therefore, the equation for the line parallel to the line y = 3x - 3, and passing through the point (4, 15) is y = 3x + 3.
Answer:
$0.50 per ounce
Step-by-step explanation:
8/16=0.50
Given:
The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

To find:
The current that will produce the maximum power.
Solution:
We have,

Here, leading coefficient is negative. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
If a parabola is
, then

In the given function, a=-12 and b=120. So,



Putting x=5 in the given function, we get




Therefore, 5 watt current will produce the maximum power of 300 amperes.