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3 years ago

Find the perimeter of the

Mathematics

1 answer:

kolezko [41]3 years ago

5 0

Answer:60

Step-by-step explanation:

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How to simplify -6k +7k 12r -8 -12 n -10 +9n -3 -4x-10x -r -10r

Semmy [17]

Answer:

Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)

- 6k + 7k = 1k = k

(7 - 6 = 1)

12r - 8 - 12 = 12r - 20

(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.

n - 10 + 9n - 3 = 9n + n - 10 - 3 = 10n - 10 - 3 = 10n - 13

(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)

- 4x - 10x = 14x

(10 + 4 = 14)

- r - 10r = 11r

(r = 1 so 10 + 1 = 11)

6 0

3 years ago

The triangles are similar. If QR = 9, QP = 6, and TU = 19, find TS. Round to the nearest tenth.

Feliz [49]

QR=9
QP=6
TU=19
TS=?
Okay so the triangles are kindred, now the equation can be made
9/16=6/x
So now we are going to cross multiply
9x=114
Now divide both sides by
912 2/3
Your answer is:
TS=12.6

4 0

3 years ago

3in x 8in x 5in = ? using cubic squares!!

KonstantinChe [14]

Answer:

120

Step-by-step explanation:

4 0

3 years ago

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Equivalent fraction of 9/11

quester [9]

Answer:

1822

Step-by-step explanation:

The fraction 1822 is equal to 911 when reduced to lowest terms.

is equivalent to 9

because 9 x 2 = 18 and 11 x 2 = 22

is equivalent to 9

because 9 x 3 = 27 and 11 x 3 = 33

is equivalent to 9

because 9 x 4 = 36 and 11 x 4 = 44

8 0

3 years ago

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Use the identity (x+y)(x−y)=x2−y2 to find the difference of two numbers if the sum of the numbers is 12 and the difference of th

Natalka [10]

Answer:

The difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$ is 4.

Step-by-step explanation:

Given: The sum of the numbers is 12 and the difference of the squares of the numbers is 48.

To find the difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$

Let the two numbers be a and b, then

Given that the sum of the numbers is 12

that is a + b = 12 .........(1)

Also, given the difference of the squares of the numbers is 48.

that is $a^2-b^2=48$ ..........(2)

Using given identity $(x+y)(x-y)=x^2-y^2$

We have $(a+b)(a-b)=a^2-b^2$

Substitute the known values, we have,

$12(a-b)=48$

Divide both side 12 , we have,

$(a-b)=4$

Thus, the difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$ is 4.

8 0

4 years ago

Read 2 more answers