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sineoko [7]
4 years ago
8

A twelve-sided die has the numbers one through twelve on the faces of the die. When the die is rolled, what is the probability t

hat the number on top is an odd number?
Mathematics
1 answer:
Goshia [24]4 years ago
4 0
I believe the percentage of this is 50%. Half the numbers are even, and half are odd. Your fraction is
\frac{6}{12}
Simplified, that's a 50% probability.
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Solve the equation 3p (3p - 8) - 8 = 9p ( p - 3 + 4
pentagon [3]

Answer:

p= \frac{-8}{33}

Explanation:

Given:

3p (3p - 8) - 8 = 9p ( p - 3 + 4)

To Find:

Value of p=?

Solution:

Before solving this equation,  we will use the method of BODMAS which states that we first solve the Bracket then Off then Division then Multiplier then addition and at last subtraction.  

Now we will solve the both right and left hand side of the equation  

3p (3p - 8) - 8 = 9p ( p - 3 + 4)

9p^2-24p-8=9p^2+9p

Gruoping the like terms we get,

9p^2-9p^2-24p-9p=8

After solving the both right hand and left hand side of the equation  

-33p=8

And we get the value of p as  

p= \frac{-8}{33}

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Step-by-step explanation:

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