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sineoko [7]
4 years ago
8

A twelve-sided die has the numbers one through twelve on the faces of the die. When the die is rolled, what is the probability t

hat the number on top is an odd number?
Mathematics
1 answer:
Goshia [24]4 years ago
4 0
I believe the percentage of this is 50%. Half the numbers are even, and half are odd. Your fraction is
\frac{6}{12}
Simplified, that's a 50% probability.
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Is a exponent determined by the amount of zeros in the number?
Alex777 [14]
Yup, the amount of 0's is the exponent. for example 1000= 10^3, hope this helped :)
3 0
3 years ago
Topic: Absolute Value Equations and Inequalities
jolli1 [7]

The values of  x are -22 and -2 and there are not extraneous solutions

<h3>How to solve the equation?</h3>

The equation is given as:

2|x + 7|= x - 8

Expand the absolute bracket

|2x + 14|= x - 8

Remove the absolute bracket

2x + 14 = x - 8 and 2x + 14 = -x + 8

Evaluate the like terms

x = -22 and 3x = -6

This gives

x = -22 and x = -2

Hence, the values of  x are -22 and -2 and there are not extraneous solutions

Read more about absolute value expressions at:

brainly.com/question/24368848

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4 0
2 years ago
How many cents is equal $¼​
Hitman42 [59]

Answer:

25 Cents

Step-by-step explanation:

1 / 4 = 0.25 = 25 cents

3 0
3 years ago
The expression n2 + n represents the total number of blocks used in the nth figure of a pattern. Use the equation n2 + n = 56 to
Brrunno [24]

We have to solve this quadratic equation n^{2}+n=56 for n to get <em>which figure has 56 blocks</em>.

n^{2}+n=56\\n^{2}+n-56=0

For middle term factorization, we need <em>two numbers that multiplied gives us -56 and added gives us 1 (coefficient of n).</em>

<em>Such two numbers are </em><em>8</em><em> and </em><em>-7</em><em>. We can now write,</em>

<em>n^{2}+n-56=0\\(n+8)(n-7)=0\\n=-8, 7</em>

<u><em>"There is no negative figure number possible, so we disregard -8"</em></u>

Our answer is 7.


ANSWER: The 7th figure has 56 blocks.


3 0
3 years ago
Read 2 more answers
A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week
Travka [436]

Answer:

solution is given below

Step-by-step explanation:

A simple random sample size n = 250 . Of the 250 employed individuals ​surveyed,42 responded that they did work at home at least once per week.

Construct 99% confidence interval for population

For proportion : 42 / 250 = 1/10 = 0.16

Mean = 2.5 * sqrt [ 0.1 * 0.9  / 250]

     = 2.5 * 0.01

    = 0.47

Construction of hypothesis:

0.10 - 0.047 < p < 0.10 + 0.047

4 0
4 years ago
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