Can you please add the picture with the problem, then I will answer your question ?
The conversion of feet to meters is obtained by multiplying 1 foot = 0.3048 meters.
<h3>What are the basic measurements for length?</h3>
Foot, inches, centimeters, and meters are the basic measuring units for length.
<h3>What are the basic conversions?</h3>
The basic conversions are:
1 kilometer = 1000 meters
1 meter = 100 cm
1 cm = 10 mm
1 mm = 0.03937 inch
1 inch = 0.0833 feet.
<h3>How to convert feet to meters?</h3>
According to the international system of units,
1 foot = 12 inches ...(1)
But we know,
1 inch = 25.4 mm, 1 mm = 0.1 cm, and 1 cm = 0.01 m
By substituting all of these in equation (1), we get
1 foot = 12(25.4 mm)
= 304.8 mm
= 304.8 (0.1 cm)
= 30.48 cm
= 30.48(0.01 m)
= 0.3048 meters
Therefore, 1 foot = 0.3048 meters.
Learn more about converting measuring units here:
brainly.com/question/174910
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Answer:7/9
Step-by-step explanation:
Answer:
(−0.103371 ; 0.063371) ;
No ;
( -0.0463642, 0.0063642)
Step-by-step explanation:
Shift 1:
Sample size, n1 = 30
Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm
Shift 2:
Sample size, n2 = 25
Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17
Mean difference ; μ1 - μ2
Zcritical at 95% confidence interval = 1.96
Using the relation :
(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)
(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)
Lower boundary :
-0.02 - 0.0833710 = −0.103371
Upper boundary :
-0.02 + 0.0833710 = 0.063371
(−0.103371 ; 0.063371)
B.)
We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.
C.)
For sample size :
n1 = 300 ; n2 = 250
(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)
Lower boundary :
-0.02 - 0.0263642 = −0.0463642
Upper boundary :
-0.02 + 0.0263642 = 0.0063642
( -0.0463642, 0.0063642)
