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2 years ago

What property should be used to solve this one-step equation : a-3=7

Mathematics

1 answer:

Aleks04 [339]2 years ago

6 0

Answer:

Step-by-step explanation:

a - 3 = 7 ( add 3 to both sides )

a - 3 + 3 = 7 + 3 , that is

a = 10

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C is the circumcenter of APQR. PC=3x+7, RC=5x-15, & QC=51-X x=[?]

amm1812

Answer:

x = 11

Step-by-step explanation:

C is the circumcenter of $\triangle PQR$

$\implies PC=QC=RC$ (Radii of same circle)

$\implies RC=QC$

$\implies 5x-15=51-x$

$\implies 5x +x=51+15$

$\implies 6x =66$

$\implies \: x = \frac{66}{6} \\ \\ \implies \: \huge \: \red{x = 11}$

8 0

2 years ago

25.(01.05)

yKpoI14uk [10]

105 but I need 20 characters to

8 0

2 years ago

Read 2 more answers

I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)

Dahasolnce [82]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

$IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =16-6.2\\ =9.5$

The interquartile range of the data is

$IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =15.5-8\\ =7.5$

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

6 0

1 year ago

Explain the steps needed to determine the value of the expression shown below be sure to provide the correct value of the expres

inn [45]

Answer:

-3/2

Step-by-step explanation:

In the picture attached, the complete question is shown.

The expression is:

$\frac{ \frac{1}{2} }{ \frac{-2}{5}} + \frac{-1}{4}$

You can rewrite the first term, expressing the division as a multiplication, that is, inverting the fraction in the denominator, as follows:

$\frac{1}{2} \times \frac{-5}{2}+ \frac{-1}{4}$

$\frac{-5}{4} + \frac{-1}{4}$

The addition of a negative fraction is simply the subtraction by that fraction:

$\frac{-5}{4} - \frac{1}{4}$

$\frac{-5 - 1}{4}$

$\frac{-6}{4}$

Which can be simplified dividing by two both numerator and denominator:

$\frac{-3}{2}$

8 0

2 years ago

HELP with these questions

zlopas [31]

Step-by-step explanation:

transform the parent graph of f(x) = ln x into f(x) = - ln (x - 4) by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

0 = ln (x - 4)

$e^{0} = e^{ln (x - 4)}$

1 = x - 4

+4 +4

5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

1 = ln (x - 4)

$e^{1} = e^{ln (x - 4)}$

e = x - 4

+4 +4

e + 4 = x

6.72 = x

(6.72, 1)

Domain: x - 4 > 0

+4 +4

x > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ into f(x) = - 3ˣ⁺⁵ by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0. the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

= - 3⁰⁺⁵

= - 3⁵

= -243

Horizontal Asymptote: y = 0 (explanation above)

5 0

3 years ago