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zimovet [89]
2 years ago
14

in a farm there are 600 mango trees. the number of trees in each row is 10 less than twice the number of rows. does each row hav

e 50 trees?
Mathematics
1 answer:
iren [92.7K]2 years ago
4 0

The area of the farm is the number of trees on it.

Each row of the farm does not have 50 trees

Let

<em />x \to<em> number of rows</em>

<em />y \to<em> number of trees in each row</em>

<em />

So, we have:

<em />y = 2x - 10<em> --- twice less than the number of rows</em>

The area of the farm is:

Area = x \times y

Where

Area = 600 --- the number of trees

So, we have:

x \times y = 600

Substitute y = 2x - 10

x \times (2x - 10) = 600

Substitute 50 for x

50 \times (2 \times 50 - 10) = 600

50 \times (100 - 10) = 600

50 \times 90 = 600

4500 = 600

The above equation is not true.

This means that, each row does not have 50 trees

Read more about areas at:

brainly.com/question/16418397

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Suppose you select a sample of 12 individuals and find that 10 of them do not exercise regularly. Assuming that the Surveillance
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Answer:

a. mean = 6.96 , standard deviation = 1.71 b. 0.0641

Step-by-step explanation:

Here is the complete question

According to the Behavioural Risk Factor Surveillance System, 58% of all Americans adhere to a sedentary lifestyle (sedentary means does not exercise).

a. If you selected repeated samples of 12 from the U.S. population, what would be the mean number of individuals per sample who do not exercise regularly? What would be the standard deviation?

b. Suppose you select a sample of 12 individuals and find that 10 of them do not exercise regularly. Assuming that the Surveillance System is correct, what is the probability that you would have obtained results as bad or worse than expected?

<em>Solution</em>

a. Since we can only have two types of outcomes, that is, those who exercise and those who do not exercise, the problem follows a binomial distribution.

Since the probability of those who do not exercise, p = 58 % = 0.58,

the mean of the binomial distribution μ = np where n = sample number = 12

So, μ = 12 × 0.58 = 6.96

The standard deviation of a binomial distribution σ = √(npq) where q = probability that people exercise = 1 - p = 1 - 0.58 = 0.42

So, σ = √(12 × 0.58 × 0.42) = √2.9232 = 1.71

b. To find the worst case, we consider the probability that at best, two exercise. Since two exercise, the probability that at best two exercise is ¹²C₂q²p¹⁰ + ¹²C₁qp¹¹ + ¹²C₀q⁰p¹²

= (12 × 11/2)(0.42)²(0.58)¹⁰ + 12(0.42)(0.58)¹¹ + 1 × (0.42)⁰(0.58)¹²

= 0.05 + 0.0126 + 0.00145

= 0.06405

≅ 0.0641

6 0
4 years ago
Evaluate the expression when c=21 and d=4.<br> c-5d
vekshin1

\huge \boxed{\mathfrak{Question} \downarrow}

  • Evaluate the expression when c = 21 and d = 4, c - 5d = ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

Given,

  • c = 21
  • d = 4
  • c - 5d = ?

Let's solve it now :-

\sf \: c - 5d \\  \\  \sf \: Substitute \: the \: values \: of \: c \: and \: d \\  \\ \sf c - 5d \\  \rightarrow \sf(21) - 5(4) \\ \sf  \rightarrow21 - 20 \\  =    \boxed{\boxed{\bf \: 1}}

  • The value of the expression is <em><u>1</u></em><em><u>.</u></em>
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