<em><u>True staments are:</u></em>
The y-variable will be eliminated when adding the system of equations
There is only one solution to the system of equations
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
x + 6y = 16 ----- eqn 1
8x - 6y = -2 ---- eqn 2
We have to solve the system of equations
When we add eqn 1 and eqn 2, then y term will get eliminated
Let us add eqn 1 and eqn 2
x + 6y + 8x - 6y = 16 - 2
6y and -6y will get eliminated
Thus, y-variable will be eliminated when adding the system of equations
x + 8x = 14
9x = 14
x = 1.55
Substitute x = 1.55 in eqn 1
1.55 + 6y = 16
6y = 16 - 1.55
6y = 14.45
y = 2.408
Thus the solution is x = 1.55 and y = 2.408
There is only one solution to the system of equations
Using Lagrange multipliers, we have the Lagrangian
with partial derivatives (set equal to 0)
Substituting the first three equations into the fourth allows us to solve for
:
For each possible value of
, we get two corresponding critical points at
.
At these points, respectively, we get a maximum value of
and a minimum value of
.
The two solutions are 3 and 6. This means that you can write your parabola as
Answer: ten times 3 x ^2
Step-by-step explanation:
Answer:
Step-by-step explanation:
First convert £ 300 to Yen
£1 = ¥ 168
£300 = 168 * 300 = ¥ 50400
As bank as ¥ 1000 notes, the money he get is ¥50,000
50000 ÷ 1000 = 50
Kevin gets 50 notes of ¥ 1000