Answer:
B
Step-by-step explanation:
These girls really need to get their cookie situation organized!
Alright, so... first let's get this problem into a simpler form.
They made 3/5 of the total, then 2 dozen which = 24 and they still have to make 1/3 more.
So to make 3/5 and 1/3 more compatible, find the LCM of the Denominator. This = 15. 5*3=15 so take 3 (from 3/5) and multiply by 3, which is 9.
This turns 3/5 to 9/15
Then do the same to the other fraction. The Denominator (3) x 5 = 15, so take the Numerator (1)x5= 5.
This turns 1/3 to 5/15
Now that this is a little more clear, let's look at the problem with our equal and substituted values.
They made 9/15 of the total, then 2 dozen which = 24 and they still have to make 5/15 more.
So from this, we can see that after they made 24 (2 Dozen) that they need 5/15 more. 15/15 would mean they're done, so that minus 5/15 = 10/15.
The difference from 9/15 & 10/15 is 1/15. This is how much was added when they made 24 more. So now we know that 1/15=24.
With this information, we can finally solve the problem.
They plan to bake 15/15 of the cookies. This is just a term that is equal to 1 whole. The "whole" is the whole amount of cookies being baked. Since 1/15=24, we can figure out 15/15 by taking 15x24.
15 x 24 = 360. So they made 360 cookies. Sounds delicious.
I hope this helped! And hopefully these imaginary friends sell all 360 cookies!
15 songs cost $9.75.
To find the cost of each song, divide the two numbers.
9.75/15 = 0.65
Each song costs $0.65.
For 18 songs,
18 × 0.65 = 11.7
18 songs cost $11.70.
To find the number of songs you can buy with $20 (x=number of songs),
0.65x = 20
x = 30.8
Since you're buying songs, you can only have a whole number. This means you must round down to 30.
You can buy 30 songs with $20.00.
Answer:
-7 is what i got
Step-by-step explanation:
combine like terms.. 6n -2n= 4n
7-14= -7
4n-7= 5n+1
+1 becomes -1
4n- -6=5n
-4n on both sides
-6= 1n
1-1 on both sides to cancel out
n= -7
(a−b)(a(2)+ab+b(2))
=(a+−b)(a(2)+ab+b(2))
=(a)(a(2))+(a)(ab)+(a)(b(2))+(−b)(a(2))+(−b)(ab)+(−b)(b(2))
=2a2+a2b+2ab−2ab−ab2−2b2
=a2b−ab2+2a2−2b2