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Reil [10]
3 years ago
13

Find k if (x+1) 2x^3+kx^2+1

Mathematics
1 answer:
Viktor [21]3 years ago
3 0
<h2>Question:</h2>

Find k if (x+1) is a factor of 2x³ + kx² + 1

<h2>Answer:</h2>

k = 1

<h2>Step-by-step explanation:</h2>

The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.

<em>This is because;</em>

i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.

ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e

=> (-3)² - 9

=> (9) - 9 = 0

Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.

<em><u>From the question</u></em>

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e

2(-1)³ + k(-1)² + 1 = 0

2(-1) + k(1) + 1 = 0

-2 + k + 1 = 0

k - 1 = 0

k = 1

Therefore the value of k is 1.

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Which function is equivalent to F(x)=-4(x+7)^2-6?
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\huge\mathfrak\orange{answer}

Simplify this quadratic function given in vertex form into standard form by simplifying the exponents and adding like terms.

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3 years ago
What must be the sides of an equilateral triangle so that it's area should be equal to the area of an isosceles triangle with ba
d1i1m1o1n [39]

Answer:

The sides of the equilateral triangle are 11.7 m.

Step-by-step explanation:

Let's find the area of the isosceles triangle:

A_{i} = \frac{bh}{2}

Where:

b: is the base = 12 m

h: is the height

We can find the height by using Pitagoras:

x^{2} = \frac{b^{2}}{2} + h^{2}    

Where:

x is the hypotenuse = side of the triangle = 10 m

h = \sqrt{x^{2} - \frac{b^{2}}{2}} = \sqrt{(10)^{2} - 6^{2}} = 8 m

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Now, since the area of the isosceles triangle is equal to the area of the equilateral triangle:

A_{e} = A_{i} = 48 m^{2}

A_{e} = \frac{bh}{2}

The height of the equilateral triangle is given by:

b^{2} = \frac{b^{2}}{2} + h^{2}    

h = \sqrt{b^{2} - \frac{b^{2}}{2}} = \frac{b}{\sqrt{2}}

Hence, the sides are:

A_{e} = \frac{1}{2}b\frac{b}{\sqrt{2}} = \frac{b^{2}}{2\sqrt{2}}            

b = \sqrt{A*2\sqrt{2}} = \sqrt{48*2\sqrt{2}} = 11.7 m      

Therefore, the sides of the equilateral triangle are 11.7 m.

I hope it helps you!      

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