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2 years ago

What's the answer will give brainliest

Mathematics

2 answers:

raketka [301]2 years ago

8 0

Answer:

2.964

Step-by-step explanation:

Elis [28]2 years ago

8 0

Answer:

2.964

Step-by-step explanation:

4 - 1.036= 2.964

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kakasveta [241]

i can't really see the image but i'm sure it's pretty cool (:

8 0

3 years ago

The sum of two numbers is 19. Their difference is 65. What are the numbers?

Ludmilka [50]

X = 42 and y = - 23 are the two numbers

3 0

3 years ago

PLEASE HELP 50 POINTS

Arada [10]

Answer:

im leaning on parallelogram

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Sam has $3.30 in quarters and dimes, and the total number of coins is 18. How many quarters and how many dimes?

zhuklara [117]

Answer:

Quarters: 10

Dimes: 8

Step-by-step explanation:

Constraints

value: 0.25q + 0.10d = 3.30

count: q + d = 18

q = 18 - d

0.25(18-d) + 0.10d = 3.30

4.50-0.25d+0.10d = 3.30

4.50-0.15d = 3.30

-0.15d = -1.20

d = 8

q + d = 18

q + 8 = 18

q = 10

Check:

0.25(10) + 0.10(8) = 3.30

2.5+ 0.80 = 3.30

3.30 = 3.30

4 0

3 years ago

Log(x-2)+log2=2logy<br>log(x-3y+3)=0

In-s [12.5K]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right$

$===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}$

$\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac$

$y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D$

$\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D$

4 0

3 years ago