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2 years ago

The points (0 1) and (1 4) are contained in the graph of an equation with only two variables x and y

Mathematics

1 answer:

Blababa [14]2 years ago

7 0

The line that passes through (0 1) and (1 4) is a linear equation

The equation of the points is y = 3x + 1

<h3>How to determine the equation of the points?</h3>

The points are given as:

(x,y) = (0 1) and (1 4)

Start by calculating the slope (m)

m = (y₂ - y₁)/(x₂ - x₁)

So, we have:

m = (4 - 1)/(1 - 0)

Evaluate

m = 3

The equation is then calculated as:

y = m(x - x₁) + y₁

This gives

y = 3(x - 0) + 1

Evaluate the product

y = 3x + 1

Hence, the equation of the points is y = 3x + 1

Read more about linear equations at:

brainly.com/question/1884491

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What is 0.86/5-0.3*0.5

grigory [225]

0.86/5-0.3*0.5= 2 answers

1. can be 11/500

2. it can be 0.022 but im positive it has to be 11/500

5 0

3 years ago

Read 2 more answers

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

Plz answer these 2 i really need help I'm not all that smart

kati45 [8]

Answer: 141.7 cm3

Explanation: you multiple 6.1, 6.7, 10.4 then divide by 3 which equals 141.68. Round it and we’re left with 141.7 cm3.

8 0

3 years ago

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HElPP what is 232 if it's scaled down by a factor of 1/10

Lynna [10]

Answer:

23.2

Step-by-step explanation:

Scaling down by a factor of 1/10 is equal to dividing the number by 10.

So 232 getting scaled down by a factor of 1/10 is equivalent to 232/10 i.e. 23.2.

3 0

3 years ago

suppose someone tells you that she has a triangle with sides having lengths 2.6,8.1 and 8.6. Is this a right triangle? why or wh

sveta [45]

If you're only provided with the lengths of a triangle, and you're asked to determine whether or not the triangle is right or not, you'll need to rely on the Pythagorean Theorem to help you out. In case you're rusty on it, the Pythagorean Theorem defines a relationship between the legs of a right triangle and its hypotenuse, the side opposite its right angle. That relationship is a² + b² = c², where a and b are the legs of the triangle, and c is its hypotenuse. To see if our triangle fits that requirement, we'll have to substitute its lengths into the equation.

How do we determine which length is the hypotenuse, though? Knowledge that the hypotenuse is always the longest length of a right triangle helps here, as we can clearly observe that 8.6 is the longest we've been given for this problem. The order we pick the legs in doesn't matter, since addition is commutative, and we'll get the same result regardless of the order we're adding a and b.

So, substituting our values in, we have:

(2.6)² + (8.1)² = (8.6)²

Performing the necessary calculations, we have:

6.76 + 65.61 = 73.96
72.37 ≠ 73.96

Failing this, we know that our triangle cannot be right, but we do know that 72.37 < 73.96, which tells us something about what kind of triangle it is. Imagine taking a regular right triangle and stretching its hypotenuse, keeping the legs a and b the same length. This has the fact of increasing the angle between a and b. Since the angle was already 90°, and it's only increased since then, we know that the triangle has to be obtuse, which is to say: yes, there's an angle in it larger than 90°.

3 0

3 years ago