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WITCHER [35]
3 years ago
13

Generate an equivalent expression using prime factorization for -60. show your workk ​

Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

60 70 80m9

Step-by-step explanation:

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-16+5n=-7(-6+8n)+3<br><br> what is the work for this ?? this is the like only one i cant get
uranmaximum [27]
-16 + 5n = -7(-6 + 8n) + 3   Given
-16 + 5n = 42 - 56n + 3   Distribute
-16 + 5n = 45 - 56n   Collect like terms
61n = 61   Add 56n to the left side and add 16 to the right side
n = 1   Divide 61 from both sides

The answer is n = 1. Remember that when you have a number beside two or more numbers in parentheses, you have to distribute, or multiply the number outside the parentheses by each number inside the parentheses.

Hope this helps!
4 0
4 years ago
Can anyone help me find the percentage?
taurus [48]
So are you finding the % of 160 out of 260?
5 0
3 years ago
Guys please help me . How to solve it
motikmotik

lol id i would help if i knew it

8 0
3 years ago
How do I prepare for the PSAT? Every time I take a practice test, I get stuck on a problem that is within my topic range, but fo
melamori03 [73]

Answer:

Maybe you can have someone read it to you to see if you can answer it that way after you answer it on your own a cupple of times

Step-by-step explanation:

8 0
3 years ago
I don’t get it. <br> Use the net to find the lateral area of the prism.
sesenic [268]

the net is pretty much the net of a long box, kinda like the one in the example in the picture below.  Due to that, we can pretty much assume the two sides sticking up and down, are just two small 6x3 rectangles, namely, they have a height of 3, reason why we assume that, if that if we fold the other sides to make out the box, those two sides sticking out, must be 3m to neatly snugfit.


now, if we close the box as it stands, the sides(laterals) will be on the left-right sides two 3x15 rectangles, and on the front-back sides, two 6x15 rectangles.


we're excluding the top and bottom sides, because those are not "laterals", or sides of the box.


\bf \stackrel{\textit{two rectangles, left and right}}{2(3\cdot 15)}+\stackrel{\textit{two rectangles, front and back}}{2(6\cdot 15)}&#10;\\\\\\&#10;90+180\implies 270

6 0
4 years ago
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