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Crazy boy [7]
3 years ago
10

Give the equation of the circle that is tangent to the y-axis and Center is (-3,2).

Mathematics
2 answers:
joja [24]3 years ago
8 0
The formula<span> for the </span>equation<span> of a </span>circle<span> is (x – h)</span>2+ (y<span> – k)</span>2<span> = r</span>2<span>, where (h, k) represents the coordinates of the </span>center<span> of the </span>circle<span>, and r represents the radius of the </span>circle<span>. If a </span>circle<span> is </span>tangent<span> to the x-</span>axis<span> at (</span>3,0), this means it touches the x-axis at that point. hope this helps

- Ava<3
yulyashka [42]3 years ago
3 0
So... check the picture below

notice, the circle is tangent to the y-axis, namely, bordering it
so. surely you can see what the radius of it is

thus   \bf \qquad \qquad \textit{equation of a circle}&#10;\\\\&#10;(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2&#10;\qquad center\ ({{ h}},{{ k}})\qquad&#10;radius={{ r}}

use the provide h,k and get use the radius for "r"

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