Is their any multiple questions
Answer: The line already goes thru 6,2 because 6=1/3(2) So the equation is y=1/3x
Step-by-step explanation:
(y-2)=1/3(x-6)
y-2=1/3x-6/3
y=1/3x
For

to be continuous at

, you need to have the limit from either side as

to be the same.


If

and

, then the limit from the right would be

, so the answer to part (1) is no, the function would not be continuous under those conditions.
This basically answers part (2). For the function to be continuous, you need to satisfy the relation

.
Part (c) is done similarly to part (1). This time, you need to limits from either side as

to match. You have


So,

and

have to satisfy the relation

, or

.
Part (4) is done by solving the system of equations above for

and

. I'll leave that to you, as well as part (5) since that's just drawing your findings.
Multiplication and division with the powers of ten
So, when multiply powers of ten, all you have to do add up the powers.
The reverse goes when you are dividing. You would subtract the powers.
9 x 10^7 => 3 x 10^3
The words " how many times as large as " indicates that we are going to divide the two, making it look like this:

Divide the 9 by 3 you get 3
Then subtract 10^3 from 10^7
Therefore, the answer is 3 x 10^4, or A
13. if edward wins 6 of his remaining games...that would make a total of 12 wins (since he already won 6 earlier)
3/4 as many winsa as edward....3/4(12) = 36/4 = 9...so he would have to win 9 to have 3/4's as much as edward...and howard has already won 4...so he needs (9 - 4) = 5....he needs 5 wins
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14. Robert has already won 2, and he has lost 8...so he would have to win at least 7 of his games to have more wins then losses