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andrezito [222]
2 years ago
5

Which is the graph for y=(x)-2? ​

Mathematics
1 answer:
Alex2 years ago
8 0
The shape of this graph is

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Using base ten blocks subtraction
GREYUIT [131]
Is their any multiple questions

4 0
3 years ago
Parallel to y=1/3x and through (6,2)
ddd [48]

Answer: The line already goes thru 6,2 because 6=1/3(2) So the equation is y=1/3x


Step-by-step explanation:

(y-2)=1/3(x-6)

y-2=1/3x-6/3

y=1/3x

5 0
3 years ago
I really really really need help!!!!
Yakvenalex [24]
For f to be continuous at x=1, you need to have the limit from either side as x\to1 to be the same.

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2
\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b

If a=2 and b=3, then the limit from the right would be 2+3=5\neq2, so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation a+b=2.

Part (c) is done similarly to part (1). This time, you need to limits from either side as x\to2 to match. You have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b
\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0

So, a and b have to satisfy the relation 4a+2b=0, or 2a+b=0.

Part (4) is done by solving the system of equations above for a and b. I'll leave that to you, as well as part (5) since that's just drawing your findings.
8 0
2 years ago
Which one is it? Plz help
Bezzdna [24]

Multiplication and division with the powers of ten

So, when multiply powers of ten, all you have to do add up the powers.

The reverse goes when you are dividing. You would subtract the powers.

9 x 10^7                    =>   3 x 10^3

The words " how many times as large as " indicates that we are going to divide the two, making it look like this:

\frac{(9)(10^{7}) }{(3)(10^{3}) }

Divide the 9 by 3 you get 3

Then subtract 10^3 from 10^7

Therefore, the answer is 3 x 10^4, or A

6 0
2 years ago
Can someone help me!!!!!!
skad [1K]
13. if edward wins 6 of his remaining games...that would make a total of 12 wins (since he already won 6 earlier)

3/4 as many winsa as edward....3/4(12) = 36/4 = 9...so he would have to win 9 to have 3/4's as much as edward...and howard has already won 4...so he needs (9 - 4) = 5....he needs 5 wins
=======================
14. Robert  has already won 2, and he has lost 8...so he would have to win at least 7 of his games to have more wins then losses
6 0
3 years ago
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