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3 years ago

Use each of these prime numbers once. Write one of them in every empty square

Mathematics

1 answer:

Ivenika [448]3 years ago

3 0

Answer: hmm can you use negative 1 multiples i dont think its possible since if 23 is the target sum you bust with every possible addition to 17

Step-by-step explanation:

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What should be done so that the expression will have a value of 10?

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Answer:

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3 years ago

Read 2 more answers

What is the surface area of this square pyramid?

Karo-lina-s [1.5K]

Answer:

A;3600 yd2

Step-by-step explanation:

The surface area is found by adding the area of the sides

The area of the bottom is

A= s^2 where s is the side length since it is a square

A = s^2 = 30^2= 900

We can find the area of one of the sides and multiply by 4 since all the sides are the same

The sides are triangles so

A = 1/2 bh where b is the base b=30 and h is the height = 45

A = 1/2 (30)* 45

A = 675

We have 4 of these triangles

4*675 =2700

Add the 4 triangles and the bottom

2700+900

3600

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3 years ago

The cost of pumpkin seeds is proportional to their weight. A 24-ounce bag of pumpkin seeds costs $6.00. What is the unit rate fo

WINSTONCH [101]

Answer:

$0.25 per ounce

Step-by-step explanation:

Look at this and now tell me if my deleted answer was right

brainly.com/question/14303747

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3 years ago

Define a variable and write an equation for each real-world problem. 1] Matt spent $ 6.50 on his lunch. This is $2.25 more than

irinina [24]

6.50-2.25=x
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4 years ago

Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti

alukav5142 [94]

Answer:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3$

Step-by-step explanation:

We want to evaluate the limit:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}$

To do so, we can divide everything by x². So:

$=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}$

Now, we can apply direct substitution:

$\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}$

Any constant value over infinity tends towards 0. Therefore:

$\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3$

Hence:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3$

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3x², and in the denominator it is x². So:

$\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}$

Simplify:

$\displaystyle =\lim_{x\to\infty}3=3$

The limit of a constant is simply the constant.

We acquire the same answer.

6 0

3 years ago