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1 year ago

Please try to answer quickly my brainly app is crashing

Mathematics

1 answer:

Ne4ueva [31]1 year ago

3 0

The formula to calculate the lateral area of a cone is given by

$LA=pi*r*l$

where

LA=10.5pi in2

r=2.1 in

l=? slant height

substitute given values

$\begin{gathered} 10.5pi=pi*2.1*l \\ solve\text{ for l} \\ l=\frac{10.5pi}{pi*2.1} \\ \\ l=5\text{ in} \end{gathered}$ <h2>The answer is 5 inches</h2>

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Rectangle JKLM is similar to rectangle WXYZ .

sladkih [1.3K]

The scale factor is 1.5

4 0

3 years ago

Read 2 more answers

-8y^3( 7y^2- 4y - 11)<br><br>How do you Factor this?

marshall27 [118]

-8y^3( 7y^2- 4y - 11)

-8y^3 (7y-11) (y+1)

8 0

3 years ago

Match the phenomenal expression on the left with the simplified version on the right

nalin [4]

Given the polynomial expression:

(y + 5)²

(y - 5)(y + 5)

Let's simplify each of the given expression:

a.) (y + 5)²

The given equation is a factor of a perfect square trinomial. For this type of expression, the following is the formula for expanding it.

$\text{ (a+b)}^2\text{ = }a^2\text{ + 2ab + }b^2$

We get,

$\mleft(y+5\mright)^2=(y)^2+2(y)(5)+(5)^2$ $(y+5)^2=y^2+10y+25$

b.) (y - 5)(y + 5)

To be able to simplify the following expression. We will be using the formula for the difference of two squares.

$(a+b)(a-b)=a^2-b^2$

We get,

$\mleft(y-5\mright)\mleft(y+5\mright)=(y)^2-(5)^2$ $(y-5)(y+5)=y^2-25^{}$

8 0

1 year ago

An object is launched directly in the air at a speed of 48 feet per second from a platform located 12 feet above the ground. The

anastassius [24]

9514 1404 393

Answer:

48 ft

Step-by-step explanation:

For the quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For the given quadratic, which defines a parabola opening downward, the axis of symmetry defines the time at which the maximum height is reached.

t = -48/(2(-16)) = 1.5

Then the maximum height is ...

f(1.5) = (-16·1.5 +48)1.5 +12 = (24·1.5) +12

f(1.5) = 48

The maximum height the object will reach is 48 feet.

6 0

3 years ago

This is for algebra 2 can someone tell me if I’m right and can someone explain how do you get a= ?

algol13

Answers:

a = 2

h = 3

k = -3

You have the correct h and k values. Nice work so far.

==========================================================

Explanation:

(h,k) is the vertex. So (h,k) = (3,-3) meaning h = 3 and k = -3

To get the value of 'a', we need to plug in some point on the red graph. Each point is of the form (x,y). We can pick any point we want that isn't the vertex.

Let's pick (0,3) which is the y intercept. I'm picking this because 0 is an easy number to work with

------------

y = a|x-h| + k

y = a|x-3| + (-3) .... plug in the h,k values

y = a|x-3| - 3

3 = a|0-3| - 3 .... plug in (x,y) = (0,3)

3 = a|-3| - 3

3 = a*3 - 3

3 = 3a - 3

3a-3 = 3

3a = 3+3 ... adding 3 to both sides

3a = 6

a = 6/3 ... divide both sides by 3

a = 2

The value a = 2 indicates that the parent function y = |x| has been stretched vertically by a factor of 2. So it is twice as tall as before. Then it has been shifted to place the vertex at (3,-3) as shown in the graph.

------------

You may be wondering why you can't pick on the vertex for (x,y)

Let's see what happens if we use (x,y) = (3,-3)

y = a|x-3| - 3

-3 = a|3-3| - 3 ... plug in (x,y) = (3,-3)

-3 = a|0| - 3 ... uh oh, we get 0 here

-3 = a*0 - 3

-3 = 0 - 3

-3 = -3

We get a true statement, which is nice, but it doesn't tell us anything about what the value of 'a' is. That 'a' term goes away entirely. So I avoided using x = 3 to prevent x-3 from being 0.

4 0

3 years ago