Answer:
i) P(X<33) = 0.9232
ii) P(X>26) = 0.001
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 30
Given that the standard deviation of the Population = 4
Let 'X' be the Normal distribution
<u>Step(ii):-</u>
i)
Given that the random variable X = 33
>0
P(X<33) = P( Z<1.5)
= 1- P(Z>1.5)
= 1 - ( 0.5 - A(1.5))
= 0.5 + 0.4232
P(X<33) = 0.9232
<u>Step(iii) :-</u>
Given that the random variable X = 26
>0
P(X>26) = P( Z>3.5)
= 0.5 - A(3.5)
= 0.5 - 0.4990
= 0.001
P(X>26) = 0.001
To find the number of years between 1844 to 2015 you have to subtract.
Lets say that x is the # of years in between 1844 and 2015
Then we have:
After doing the subtraction using a calculator or a pencil and paper, you get that:
So 171 years have passed from 1844 to reach to 2015.
The formula to find circumference is 2(3.14)r
For this problem, first you take half of the diameter to get radius. Then, putting this into the formula, you get 2(3.14)(6) = 37.699
The formula
in solving the integral of the infinity of 3 is ∫3<span>∞?</span>(1<span>)÷((</span>x−2<span><span>)<span><span>(3/</span><span>2)</span></span></span>)</span><span>dx</span>
Substitute the numbers given
then solve
limn→inf∫3n(1/((n−2)(3/2))dn
limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)
=0+2=2
Solve for the integral of 2 when 2 is approximate to 0.
Transpose 2 from the other side to make it -2
∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C
(x−2)−1/2=1x−2−−−−√
0−(3−2)−1/2−1/2=2
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