P(LC / S) = P(S intersect LC) / P(S)
P(S intersect LC) = P(S)*P(LC / S) = 0.19 * 0.158 = 0.03
Answer:
A = 26 ft²
Step-by-step explanation:
To find the area of a circle, use the formula A = πr²
We know π = 3.14 and C = 18.
Use the circumference to find "r". C = 2πr
C = 2πr
18 = 2(3.14)r
18 = 6.28r
r = 18/6.28 Exact answer
r ≈ 2.866 Rounded to three decimal places
You can use either of the two bolded "r" values. I will use the rounded answer in the formula for area.
Substitute π = 3.14 and r = 2.866.
A = πr²
A = (3.14)(2.866)² Solve exponents first
A = 3.14(8.213956) Multiply
A = 25.7918218... Unrounded answer
A ≈ 26 Rounded to nearest square foot
Add the units back in.
<h3>A = 26 ft²</h3>
Answer:
The answers are 23, 9,200 and 26, 10,400
Step-by-step explanation:
Whole numbers are numbers without decimal points greater than 0.
The set of whole numbers is:

In the introductory part of this solution, I stated that:
- Whole numbers do not have decimal point
- The smallest whole number is 0
This means that the following numbers are whole numbers:
1, 9, 10, 67
While the following numbers are not:
-1, 9.0, 1.0, -67
Let W be the set of whole numbers; the set is:

The dots after 4 means the set still continues
Read more at:
brainly.com/question/13106807
Answer:
4/675
Step-by-step explanation:
There can be 90 two-digit numbers ranging from 10 to 99. There will be
90 x 90= 8100 possibilities of randomly selecting and combining 2 entire two-digit numbers, if we find ax b to be distinct from bx a. When 10 is first chosen, there may be 9 two-digit numbers that could be combined within the required range for a product When 11 is chosen first, then the second two-digit number has 9 possibilities. 12 has seven options; 13 has six options; 14 has five options; 15 has four options; 16 has three options; 17 has two options; 18 has 2 options; and 19 has one option. It provides us 48 total choices so the likelihood that the combination of two randomly chosen two-digit whole numbers is one of theses these possibilities is thus 48/8100 = 4/675.