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konstantin123 [22]
3 years ago
9

A closet contains 8 shirts, 5 skirts, and 6 pairs of shoes. How many possible outfit combinations are there?

Mathematics
2 answers:
german3 years ago
8 0
since an outfit depends on the on the type of clothes worn @ time
  
8 shirts × 5 skirts × 6 pairs 
         = 240

Answer = 240 0utfit combination
strojnjashka [21]3 years ago
3 0

Answer:  The required number of possible outfit combinations is 240.

Step-by-step explanation:  Given that a closet contains 8 shirts, 5 skirts, and 6 pairs of shoes.

We are to find the number of possible outfit combinations.

We know that

if there are m and n number of two different types of objects, then the number of possible combinations that can be made using these objects is

m\times n.

Therefore, the number of possible outfit combinations that can be made using   8 shirts, 5 skirts, and 6 pairs of shoes is given by

N=8\times5\times6=240.

Thus, the required number of possible outfit combinations is 240.

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for a scale drawing of a bathroom, 1/4 inch represents the actual length of 1 ft., if the bathroom measures 1 1/2 inches by 2 in
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Answer:

6ft by 8ft

Step-by-step explanation:

1/4 inch = 1 ft

1 1/2 inches has six 1/4 inches

6 times 1 = 6ft

2 inches has eight 1/4 inches

8 times 1 - 8 ft

so its 6ft by 8ft

4 0
3 years ago
Write $2.161616 as a fraction and mixed number
Alona [7]
Fraction is 2.161616/1000000
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4 0
3 years ago
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geniusboy [140]

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8 0
3 years ago
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

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