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Mazyrski [523]
3 years ago
6

Its a quadratic equation I Dont know exactly how to solve it help please

Mathematics
2 answers:
Masja [62]3 years ago
5 0
1. (X-2) (x+4)
= x (x+4) -2 (x+4)
= x2 +4x -2x -8
= x2 + 2x -8
2. (X+1) (x+6)
= x(x+6) +1 (x+6)
= x2 +6x +x + 6
= x2 +7x +6
3. (X-4)(x+2)
= x(x+2) -4 (x+2)
= x2 + 2x - 4x -8
= x2 -2x -8
4. (X+5)(x-3)
= x(x-3) +5 (x-3)
= x2 -3x +5x -15
= x2 +2x -15
5. (X-6)(x-2)
= x(x-2) -6(x-2)
= x2 -2x -6x +12
= x2 -8x +12

Regards,
ArmyCee:)
Leto [7]3 years ago
3 0

Answer:

Step-by-step explanation:

(x - 2)(x + 4)

=x(x + 4) -2(x + 4)

=x^2 + 4x - 2x - 8

=x^2 + 2x - 8

(x + 1)(x + 6)

=x(x + 6) +1(x + 6)

=x^2 + 6x + x + 6

=x^2 + 7x + 6

(x - 4)(x + 2)

=x(x + 2) -4(x + 2)

=x^2 + 2x - 4x - 8

=x^2 - 2x - 8

(x + 5)(x - 3)

=x(x - 3) +5(x - 3)

=x^2 - 3x + 5x - 15

=x^2 + 2x - 15

(x - 6)(x - 2)

=x(x - 2) -6(x - 2)

=x^2 - 2x - 6x + 12

=x^2 - 8x + 12

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(x – 2) = –1/4(x – 8)
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
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fenix001 [56]

Answer:

see the explanation

Step-by-step explanation:

we have

0.888...

This is a <u>repeating decimal</u> (Is a decimal that has a digit, or a block of digits, that repeat over and over and over again without ever ending)

Convert to fraction number

Let

x=0.888...

10x=8.888...

Subtract 0.888... from 8.888... to remove the decimal

10x-x=8.888...-0.888...

9x=8

Solve for x

x=8/9

therefore

Mike fraction is incorrect

because 4/5=0.8

0.8 is a <u>terminating decimal </u>(It's a decimal with a finite number of digits)

Mike's mistake was considering the number as a terminating decimal instead of a repeating decimal

Beth is correct

because

If you divide 8/9

the result is 0.8888888...

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Answer:

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