Answer:
7
Step-by-step explanation:
410 - x/7 +70 = 120
410+70-120=x/7
360=x/7
X =2520
The difference of the length of two different squares having area of 36 square meters and 49 square meters is 1 m.
According to the question,
We have the following information:
Two different squares have an area of 36 square meters and 49 square meters.
We know that the following formula is used to find the area of square:
Area = side*side
Side*side = 36
Side = √36
Side = 6 m
Now, side of the another square:
Side*side = 49
Side = √49
Side = 7 m
Now, the difference in the length of the sides of these two squares:
7-6
1 m
Hence, the difference of the length of two different squares having area of 36 square meters and 49 square meters is 1 m.
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Answer: The answer is 20 inches.
Step-by-step explanation: As given in the question and shown in the attached figure, Keyley drew the rectangle 'R' and square 'S' with equal areas.
Also, the length of Keyley's rectangle 'R' = 8 inches. Let the breadth be 'b' inches. Again, let 'l' be the length of a side of square 'S'.
Then, we must have

Now, the only possible value of b is 2, so that

Thus, the breadth of 'R' is b = 2 inches and side of 'S' = 4 inches.
Therefore, perimeter of Keyley's rectangle 'R' is given by

Thus, the answer is 20 inches.