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3241004551 [841]

2 years ago

5

A phone company offers two monthly plans. Plan A cost $23 plus an aditional $0.10 for each minute of calls. plan B cost $19 plus

an aditional $0.14 for each minute of calls

1 answer:

PolarNik [594]2 years ago

6 0

Answer:

x=100

Step-by-step explanation:

23+.10x=19+.14x

God bless!

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Identify which of these designs is most appropriate for the given experiment: completely randomized design, randomized blockd

sasho [114]

Answer:

Matched pairs design

Step-by-step explanation:

Looking at the options;

-It's not a completely randomized design because a randomized design will assign all individuals to a group which in this case it doesn't.

- It's not a randomized block design because randomized block design will group the subjects in question into 2 or more blocks which have a common characteristic and will then randomly assign subjects in each of the blocks.

-It's a matched pair because every individual/subject undergoes measurements both before and after being treated with the drugs.

Thus, the correct option is matched pairs design.

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3 years ago

Find f(-2) for the function f (x) = 3x^2-2x+7

barxatty [35]

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23

Step-by-step explanation:

plug -2 in for x then solve

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3 years ago

Find the mean of the set of data. Use a calculator if necessary. (Remember to put the list in numerical order.)

kompoz [17]

Answer:

9.4

Step-by-step explanation:

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3 years ago

Read 2 more answers

-1/2x>-2x - (-3/4x +1)

Sergeu [11.5K]

I neeeeeeeed it skkyvbnj

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3 years ago

The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s

Molodets [167]

Answer:

500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

$f(x,y)=4x+2y\\g(x,y)=2x^2+y-4$

The Lagrangian is ...

$\mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2$

$\dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5$

Since x and y are in thousands, maximum profit is to be had when the company produces ...

500 Type A souvenirs, and 3500 Type B souvenirs

3 0

2 years ago