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Arte-miy333 [17]
3 years ago
7

What is the average rate of change of f(x) over the interval [6, 8]?

Mathematics
1 answer:
Rzqust [24]3 years ago
4 0
\dfrac{f(8)-f(6)}{8-6}=\cdots
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How many different three-letter initials with none of the letters repeated can people have?
viva [34]
This is a probablity question

there are 3 slots, 26 letters of the alphabet

so in the first slot, we have 26 possible letters
2nd slot, we have 25 possible letters (we used one for the first slot)
3rd slot, we have 24 possible letters, (we used 2 for first and 2nd slot)

so in total, we have 26*25*24 or 15600 different 3 letter initials with no repeated letters
3 0
3 years ago
I need the answer to these math questions.
Studentka2010 [4]

Answer:

1) 506.85 minutes

2) 17.33 minutes

3) 23.25 hours

Step-by-step explanation:

1) 16 minutes and 21 seconds

21\ seconds=\frac{21}{60}\\=0.35\ minutes

16 minutes and 21 seconds=16.35 minutes

Multiply by 31

\therefore 16.35\times 31=506.85\ minutes

2) 537 minutes 20 seconds

20\ seconds=\frac{20}{60}\\=0.33\ minutes

537 minutes 20 seconds=537.33 minutes

Divide by 31

\therefore 537.33\div 31=17.33\ minutes

3) 999 hours 45 minutes

45\ minutes=\frac{45}{60}\\=0.75\ hours

999 hours 45 minutes=999.75 hours

\therefore 999.75\div 43=23.25\ hours

8 0
3 years ago
What's the mean, median, and mode of 3, 5, 1, 5, 1, 1, 2, 3, 15.
lara [203]
<h3><em>Answer:</em></h3>

<em>mean = 4</em>

<em>Median = 3</em>

<em>Mode = 1</em>

Step-by-step explanation:

first let’s arrange the numbers from least to highest:

1 , 1 , 1 , 2 , 3 , 3 , 5 , 5 , 15

=====================

The median is the number that’s comes in the middle of the data set ⇒ median = 3  ( the fifth number in the data set)

1 , 1 , 1 , 2 , <u>3</u>, 3 , 5 , 5 , 15

________________________

The mode is the number that repeats the most ⇒ mode = 1  (repeated 3 times)

____________________________________

\text{the mean} =\frac{1+1+1+2+3+3+5+5+15}{9} = \frac{36}{9}=4

4 0
2 years ago
Read 2 more answers
Plssssssssssssssssssssssssssssssssssssss
svet-max [94.6K]

Answer:

The answer is B

Step-by-step explanation:

its because B is the equilateral triangle and they are asking for a prism whose base is an equilateral angle

8 0
2 years ago
Please Help Me With Matrices! Fully explain to me what to do, for I have no clue what I am doing. I can substitute, and eliminat
prohojiy [21]
Can you find an explanation of "row operations" with examples in any of your learning materials, online or in print?

Once you get the hang of row ops, it's not terribly hard.  This does, however, take a lot of arithmetic.

<span>−6x−y−5z=−10
− 5x+6y+4z=−7 
2x−3y−2z=3 

can be represented by the matrix  

-6  -1  -5  -10
-5    6  4   -7
 2   -3  -2    3

Our goal is to transform this 3 x 4 matrix so that it ends up looking like:

1  0  0  a
0  1  0  b
0  0  1  c

and the solution you want is the vector (a, b, c) (three numeric values).

</span>I have more or less arbitrarily chosen to start with the third row:   
2   -3  -2    3.  We want this row to begin with a 1, so we multiply each of the original four digits by (1/2), obtaining 1   -3/2   -2/2   3/2, or 1  -3/2   -1   3/2.

We can present the original matrix in any order without changing its value.  Thus, the original 

-6  -1  -5  -10
-5    6  4   -7
 2   -3  -2    3

becomes 

-6  -1    -5  -10
-5    6     4   -7
 1  -3/2  -1   3/2

We want that "1" to appear in the upper, left hand corner of the matrix.  We are free to interchange rows, so we interchange the first and 3rd rows, obtaining 

1  -3/2  -1   3/2
-5    6     4   -7
-6  -1    -5  -10

Next, we manipulate the first row (which begins with 1) so as to get the first element of the 2nd and 3rd rows to be 0.

To achieve this for the 2nd row, we multiply the 1st row by 5, obtaining

5   -15/2   -5   15/2

and then we add this to the existing 2nd row.  The result will be an "0"
in the first column:

0   (6-15/2)   ( 4-5)  (-7+15/2), or   0   -3/2   -1   1/2.

Substitute this new 2nd row for the original 2nd row.  We'll now have:

  1  -3/2  -1   3/2
  0  -3/2   -1   1/2
-6  -1    -5  -10

Now we have to "fix" the 3rd row, so that it starts with a zero (0):
To accomplish this, mult. the first row by 6 and add the resulting new row to the existing 3rd row.  Result should be  0  -10  -11  -1, and the revised matrix will be 

 1  -3/2  -1   3/2
  0  -3/2   -1   1/2
 0  -10    -11  -1

Next steps involve transforming the 2nd column so that it looks lilke

0
1
0.

To do this, mult. the entire 2nd row by -2/3,  Here's the expected result:

0    1     2/3    -1/3

Replace the existing 2nd row with this revised 2nd row:

 1  -3/2  -1   3/2
  0  -3/2   -1   1/2
 0  -10    -11  -1  becomes

 1  -3/2  -1   3/2
 0    1    2/3   -1/3
 0  -10    -11  -1

In the end we want this matrix to look like 

1  0  0  a
0  1  0  b
0  0  1  c

and the solution you want is the vector (a, b, c) (three numeric values).

Use this new 2nd row to further fix the 2nd column, so that it looks like

0 
1
0.


I ask that you go thru this discussion and work out each set of calculations yourself, to verify what I have done so far.  Reply with any questions that arise.  We'll find a way to finish this solution.

8 0
3 years ago
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