All categories

3 years ago

F(x) = 3x^2 -15 g(x) = 1 -2/3x

Mathematics

1 answer:

Oliga [24]3 years ago

8 0

Answer:

f(g(-6)) is equal to 60

Step-by-step explanation:

We can simply solve this by first plugging -6 into function 6, and then applying function f to the result of that.

$f(g(-6))\\= f(1 - \frac{2(-6)}{3})\\= f(1 - \frac{-12}{3})\\\\= f(1 + 4)\\= f(5)\\= 3(5)^2 - 15\\= 3 * 25 - 15\\= 75 - 15\\= 60$

You might be interested in

Evaluate 128 divided by (2^2)^3 - 3^3

svet-max [94.6K]

Answer:

-25

Step-by-step explanation:

Order of Operations

8 0

3 years ago

Bir sınıftaki erkekletin sayısının kızların sayısına oranı 3 bölü 4 tür . sınıftaki kız öğrencilerin sayısı 12 ise erkek oğrenci

VikaD [51]

Answer:

Ha?what do you mean ba? Jjsjsjsjjsjs

5 0

2 years ago

Read 2 more answers

Please answer the question with words

dangina [55]

Words words words words words words words words words words words words words words words words words words

7 0

3 years ago

Verify csc^2t-cos t sect= cot^2 t

Ymorist [56]

Rewriting the left hand side,

csc²t - cost sec t

= (1/sin²t)-(cost)(1/cost)

= 1/sin²t - 1

= 1/sin²t - sin²t/sin²t

= (1-sin²t)/sin²t

= cos²t/sin²t

= cot²t

7 0

2 years ago

Read 2 more answers

The Department of Commerce in a particular state has determined that the number of small businesses that declare bankruptcy per

skad [1K]

Answer:

B) 0.1487

Step-by-step explanation:

Let $X$ be the discrete random variable that represents the number of events observed over a given time period. If $X$ follows a Poisson distribution, then the probability of observing $k$ events over the time period is:

$P(X=k)=\frac{\lambda^{k} *e^{-\lambda} }{k!}$

Where:

$\lambda=Mean\\k=number\hspace{3}of\hspace{3}events\\e=Euler's\hspace{3}number$

So, the probability that exactly 5 bankruptcies occur next month is:

$P(X=5)=\frac{6.4^{5} *e^{-6.4} }{5!} =\frac{17.84083537}{120} =0.1486736281\approx0.1487$

4 0

2 years ago