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REY [17]
3 years ago
12

Round 2.71828 to the hearest thousandth.

Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0

Answer:

2.718

Step-by-step explanation:

The thousandths place is 3 to the right of the decimal (the 8).

Since the next number is 2, the number stays the same and does not round up.

Hope this helps :)

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The average distance in miles traveled in one hour if 660 miles can be covered in 1.5 hours
mariarad [96]

Answer:

440

Step-by-step explanation:

1.5 hours he 90 minutes

660/ 90=7.333

7.333*60 (which is how many minutes in an hour = 440 miles

6 0
3 years ago
The figure below shows a quadrilateral ABCD with diagonal BD bisecting angle ADC:
juin [17]

Answer:

AD=DC

Step-by-step explanation:

I just took the test, and it said that this is the correct answer.

7 0
3 years ago
1. Oxygen has an electronegativity of 3.5, and carbon has an electronegativity of 2.5. How is charge distributed on an oxygen at
torisob [31]

Answer:

1-

Step-by-step explanation:

because 1 was removed from it

7 0
3 years ago
What is 63/80 as a decimal
Kaylis [27]
To get 63/80 converted to decimal, you simply divide 63 by 80. Don't worry. You don't need to get the calculator out, because I did this for you.

63/80 as a decimal is:

<span>0.787500</span>
7 0
3 years ago
A ship moves through the water at 30 miles/hour at an angle of 30° south of east. The water is moving 5 miles/hour at an angle o
iVinArrow [24]

Answer:

a. 25.98i - 15j mi/h

b. 1.71i + 4.7j mi/h

c. 27.69i -10.3j mi/h

Step-by-step explanation:

a. Identify the ship's vector

Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h

Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h

b. Identify the water current's vector

Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h

Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h

c. Identify the vector representing the ship's actual motion.

The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.

V = v + v'

= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h

= (25.98i + 1.71i + 4.7j - 15j )mi/h

= 27.68i -10.3j mi/h

7 0
3 years ago
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