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Murrr4er [49]
3 years ago
14

PLEASE HELP ASAP!!

Mathematics
2 answers:
Airida [17]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Hey There so the first step of this problem is to find the formula for circumference

C=2\pi r

given some of the values we can form an equation to solve for the radius (r)

31.4=3.14(2)r\\3.14(2)=6.28\\31.4=6.28r\\\frac{31.4}{6.28} =5

so we can conclude that the radius is equal to 5

ladessa [460]3 years ago
4 0

Answer:

C) 5 ft

Step-by-step explanation:

Equation used: C=2πr

This isn't a hard question once you understand the basics of it. The radius squared by 2 equals the diameter, and other way around. Your going to divide the circumference by the pie (π).

31.4 ÷ 3.14 = 10

Now you'll do 10/2 to equal 5.

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Circle O has a circumference of 132 feet. What is the approximate area of a circle O?
Archy [21]

Answer:1387.96

Please mark me as Brainliest!

Step-by-step explanation:

5 0
3 years ago
What is the minimum value for g(x)=x2−10x 16? enter your answer in the box.
motikmotik

The minimum value for g(x)=x² - 10x + 16 is -9

<h3>How to determine the minimum value?</h3>

The function is given as:

g(x)=x² - 10x + 16

Differentiate the function

g'(x) = 2x - 10

Set the function 0

2x - 10 = 0

Add 10 to both sides

2x = 10

Divide by 2

x = 5

Substitute 5 for x in g(x)

g(5)=5² - 10*5 + 16

Evaluate

g(5) = -9

Hence, the minimum value for g(x)=x² - 10x + 16 is -9

Read more about quadratic functions at:

brainly.com/question/7784687

3 0
2 years ago
Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat
likoan [24]

F+G:

F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}

Then, add the elements that occupy the same position:

H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}

Solve

H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}

So, we find the element at address h31:

H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}

In this case, position h31 is - 8.0

8 0
1 year ago
Please answer all with explanation
stepladder [879]

3b.4+y/3=2

12+y/3=2

12+y=6

y=6-12

y=-6

.

8 0
3 years ago
Use the table below to complete exercise 7
12345 [234]
C is the answer I believe
3 0
3 years ago
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