Answer:
1). t ≥ -
2). k ≥ 
3). y < -
4). b > 
5). w ≤ 0
Step-by-step explanation:
1). 




t ≥ -
2). 15k + 11 ≤ 18k - 5
15k - 18k ≤ -5 - 11
-3k ≤ - 16
3k ≥ 16
k ≥ 
3). 44y > 11 + 88y - 22y
44y > 11 + 66y
44y - 66y > 11
-22y > 11
22y < -11

y < 
4). 

(b - 27) > 
b > 
b > 
5). 11w - 8w ≥ 14w
3w - 14w ≥ 0
-11w ≥ 0
w ≤ 0
Answer:
33.5
-by-step explanation:
8.5 + (12 + 4) × 2 - 7
Use PEMDAS ( I think this is right hope it helps!)
Answer:so where is the question
Step-by-step explanation:plzz ask probably
Answer:

Step-by-step explanation:
Given:
Center of circle is at (5, -4).
A point on the circle is 
Equation of a circle with center
and radius 'r' is given as:

Here, 
Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:
Using distance formula for the points (5, -4) and (-3, 2), we get

Therefore, the equation of the circle is:

Now, rewriting it in the form asked in the question, we get

Hello! For ease of calculations, we can identify the time it took for the weight to bounce back to the other direction, then the other, and then back to its original position by looking at the time it took for the weight to change from 0 to 25 to 0 to -25 then back to 0. This is one whole cycle of the weight.
By the time the weight first reached zero, 1.5 seconds has passed. By the third time it got to zero again, 7.5 seconds has passed. Therefore, one whole cycle of the weight is 7.5-1.5 = 6.0 seconds.
ANSWER: One whole cycle of the weight took 6 seconds.