135 is the answer. please give me brainliest
Answer:
B -3x
Step-by-step explanation:
All you do is 60 times .65 so the answer is 39
Answer:
The maximum number of red beans that can be put in one of the stacks is 5.
Step-by-step explanation:
First, Every pile is made with 7 beans, but they need to have at least one bean of each color, so we need to include in the pile minimum one yellow bean and one green bean. If we make a stack with this condition, the stack is going to have: 1 yellow bean, 1 green bean, and 5 red beans.
Additionally, it is necessary to know if there are enough red beans for the other piles. In this case, we have 10 red beans so if we have 5 red beans in one stack, the other two stacks have enough red beans to fulfill with the condition to have at least one red bean.
So, the maximum number of red beans that can be put in one of the stacks is 5.
The radius is 5 so you can add 5 to the y value of the center to get (3,8)
