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sweet [91]
3 years ago
11

They keep returning and saying show work again​

Mathematics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

We conclude that:

20\times \:3\frac{1}{5}=64

Step-by-step explanation:

Given the expression

20\:\times 3\frac{1}{5}

convert mixed number to improper fraction: a\frac{b}{c}=\frac{a\times c+b}{c}

i.e. 3\frac{1}{5}=\frac{3\times 5+1}{5}=\frac{16}{5}

so the expression becomes

20\:\times 3\frac{1}{5}\:=20\times \:\frac{16}{5}

Factor the number: 20 = 5×4

              =5\times \:4\times \frac{16}{5}

Cross-cancel common factor: 5

               =4\times \:16    

Multiply the numbers: 4×16 = 64

               =64

Therefore, we conclude that:

20\times \:3\frac{1}{5}=64

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Step-by-step explanation:


This is what I get


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marin [14]

Function transformation involves changing the form of a function

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  • The x and y intercepts are -0.67 and 1.91, respectively.
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The functions are given as:

\mathbf{f(x) = log3x}

\mathbf{g(x) = 4log3(x+1)}

<u>(a) The transformation from f(x) to g(x)</u>

First, f(x) is shifted left by 1 unit.

The rule of this transformation is:

\mathbf{(x,y) \to (x + 1,y)}

So, we have:

\mathbf{f'(x) = log3(x + 1)}

Next. f'(x) is vertically stretched by a factor of 4.

The rule of this transformation is:

\mathbf{(x,y) \to (x,4y)}

So, we have:

\mathbf{g(x) = 4log3(x+1)}

Hence, the transformation from f(x) to g(x) is a horizontal shift 3 units left, followed by a vertical stretch by a factor of 4

<u>(b) Sketch of g(x)</u>

See attachment

<u>(c) Asymptotes</u>

The graphs of g(x) have no asymptote

<u>(d) The intercepts, and the behavior of f(x)</u>

The graph crosses the x-axis at x =-0.67, and it crosses the y-axis at y = 1.91

Hence, the x and y intercepts are -0.67 and 1.91, respectively.

The behavior of g(x) is that, g(x) approaches infinity, as x approaches infinity.

We know this because, the value of the function increases as x increases

Read more about function transformations at:

brainly.com/question/13810353

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slope:

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