9514 1404 393
Answer:
24
Step-by-step explanation:
Let p, d, r represent the numbers of premium, deluxe, and regular tickets sold, respectively.
p + d + r = 155 . . . . . . . number of tickets sold
8p +3d +r = 409 . . . . . revenue from tickets sold
d - p = 19 . . . . . . . . . . . relation between deluxe and premium tickets
Using the third equation, we can substitute d=19+p in the other two equations.
p + (19+p) +r = 155
8p +3(19+p) +r = 409
Subtracting the first of these equations from the second, we get ...
(11p +r +57) -(2p +r +19) = (409) -(155)
9p = 216 . . . . . . subtract 38 and simplify
p = 24 . . . . . . . . divide by 9
24 premium tickets were sold.
Kate and Will meet at 1 : 09 pm
<em><u>Solution:</u></em>
The distance between Quebec City and New York City is 520 miles.
At the point where Kate and Will meet, they would have traveled 520 miles.
Let "t" represent the time it takes Kate to travel a certain distance before they met.
If Kate drives at 55 mph, the distance covered would be
If Will drives at 75 miles per hour, then the distance covered will be
Since the total distance covered is 520 miles
Which means,
Given that in question,
If Kate leaves Quebec and will leaves New York at 9:09 a.m
4 hours after 9: 09 am, Kate and Will will meet
9: 09 am + 4 hours = 1: 09 pm
Thus they would meet at 1 : 09 pm
5 I’m not the best at math but counting to the nearest tenth that should be answer or 0
Answer:
Mona = 8, Shakira = 16
Step-by-step explanation:
S = 2m....m = S/2
2S + S = 24
3S = 24
S = 24/3
S = 8
Mona = 8
Shakira = 16
Answer:
y=4x-9y
y+9y=4x
10y=4x
Step-by-step explanation: