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Natalka [10]
3 years ago
15

What is the greatest common factor of 56 and 72

Mathematics
2 answers:
Ray Of Light [21]3 years ago
8 0

Answer: 8

Step-by-step explanation: hope this helps you!

kherson [118]3 years ago
8 0

Answer:

8!

Step-by-step explanation:

56/7 = 8

and 72/9 = 8

8 is a factor for both of those numbers! It's also the largest one!

I hope this helps!!

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8.4.9 On or off the line & Practice Problems
Andrews [41]

Answer:

Number of quarters → 15

Number of dimes → 2

Step-by-step explanation:

Let the number of dimes I have = y

And number of quarters = x

Since, I have amount in my pocket = $2

Therefore, 0.10y + 0.25x = 2

100(0.10y + 0.25x) = 100×2

25x + 10y = 200

5x + 2y = 40

2y = -5x + 40

y = -2.5x + 20 ---------(1)

Total number of coins in my pocket = 17

x + y = 17

y = -x + 17 ---------(2)  

By using a graphing calculator we can graph these two lines (As attached)

Solution of the given system of equations will be the point of intersection of these lines.

Solution → (2, 15)

Number of quarters → 15

Number of dimes → 2

4 0
3 years ago
F(x)=6x^2 +10x−1
KATRIN_1 [288]

Answer: It has two distinct real zeros.

Step-by-step explanation:

The formula that is used to calculate the discriminant of a Quadratic function is the one shown below:

D=b^2-4ac

In this case you have the following Quadractic function provided in the exercise:

f(x)=6x^2 +10x-1

Let's make it equal to 0:

0=6x^2 +10x-1

You can identify that:

a=6\\\\b=10

Knowing these values, you can substitute them into the formula and then evaluate:

D=10^2-4(6)(-1)\\\\D=124

Therefore, since:

 D>0

You can determine that the it has two distinct real roots.

3 0
3 years ago
Please please open !
Tomtit [17]

Answer:

1.A  2.A  3.A 4.B  5.A  6.B

6 0
3 years ago
Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0
3 years ago
There is a bag with only red marbles
Paha777 [63]

Answer:

14 red marbles.

Step-by-step explanation:

If I am reading this correctly, since the probablitly of choosing a blue marble is 7/9, then 7/9 of the bag must be blue marbles. That amounts to 7/9*63=49 and the bag containing 49 blue marbles. Therefor, 63-49=14 is the number of red marbles in the mag.

6 0
2 years ago
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